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Fittoniya [83]
2 years ago
5

Finn and Ellie sell oranges at a produce stand. Finn earns $5 for each crate of oranges he sells. At the end of the week, Ellie

has earned $20 more than Finn. The following expression shows Ellie's earnings:
20 + 5z

In the expression, what does the second term represent?

a. Finn's earnings at the end of the week
b. The number of crates of oranges Ellie sold
c. Ellie's earnings at the end of the week
Selected:d. The number of crates of oranges Finn sold
Mathematics
1 answer:
KatRina [158]2 years ago
3 0

The second term in the expression represents a. Finn's earnings at the end of the week.

To answer the question, we need to know what mathematical expressions are.

<h3>What are mathematical expression?</h3>

Mathematical expressions are expressions that show the relationship between two variables.

<h3>Finn's earnings</h3>

Now, let z be the number of crates Finn sold.

Since Finn earns $5 per crate, the total amount he earns at the end of the week is t = amount per crate × number of crates

= 5 × z

= 5z

<h3>Ellie's earnings</h3>

Now since Ellie earns $20 more than Finn, the amount Ellie earns is

T = 20 + t

= 20 + 5z.

So, 5z the second term in the expression represents Finn's earnings at the end of the week.

So, the second term in the expression represents a. Finn's earnings at the end of the week.

Learn more about mathematical expressions here:

brainly.com/question/11258067

#SPJ1

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[10] In the following given system, determine a matrix A and vector b so that the system can be represented as a matrix equation
irina1246 [14]

Answer:

y=-\frac{158}{579}

Step-by-step explanation:

To find the matrix A, took all the numeric coefficient of the variables, the first column is for x, the second column for y, the third column for z and the last column for w:

A=\left[\begin{array}{cccc}1&1&2&2\\-7&-3&5&-8\\4&1&1&1\\3&7&-1&1\end{array}\right]

And the vector B is formed with the solution of each equation of the system:b=\left[\begin{array}{c}3\\-3\\6\\1\end{array}\right]

To apply the Cramer's rule, take the matrix A and replace the column assigned to the variable that you need to solve with the vector b, in this case, that would be the second column. This new matrix is going to be called A_{2}.

A_{2}=\left[\begin{array}{cccc}1&3&2&2\\-7&-3&5&-8\\4&6&1&1\\3&1&-1&1\end{array}\right]

The value of y using Cramer's rule is:

y=\frac{det(A_{2}) }{det(A)}

Find the value of the determinant of each matrix, and divide:

y==\frac{\left|\begin{array}{cccc}1&3&2&2\\-7&-3&5&-8\\4&6&1&1\\3&1&-1&1\end{array}\right|}{\left|\begin{array}{cccc}1&1&2&2\\-7&-3&5&-8\\4&1&1&1\\3&7&-1&1\end{array}\right|} =\frac{158}{-579}

y=-\frac{158}{579}

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3 years ago
What is Pythagoras Theorem ?
Nikitich [7]
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As 'C' is always the hypotenuse, you have to work out the two other lengths, and you do this by squaring the numbers.
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As you're looking for C, you've got to add these together
9+16=25
As a²+b²=c², this means that the answer for C is the square root of 25.
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