Answer:
√1370 or about 37.01
Step-by-step explanation:
use distance formula
√(x2-x1)^2+(y2-y1)^2
sqrt(8-7)^2+(41-4)^2
sqrt(1)^2+(37)^2
sqrt 1+1369
sqrt 1370
= about 37. 01
Answer:
108 cm^2
Step-by-step explanation:
rectangle + 2 triangle = total area
L x W + 2 * 1/2 base * height = total area
(5x12) + 2 * 1/2 * 12 * 4 = total area
60 + 48 = 108 cm^2
graph A
no x-intercept
no y-intercept
H.A is y = 5
V. A. is x = 0
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Answer: 
<u>Step by step explanation:</u>
log₆(5x + 6) - log₆(x - 4) = 2
log₆
= 2
= 6²
= 36
5x + 6 = 36(x - 4)
5x + 6 = 36x - 144
6 = 31x - 144
150 = 31x
= x
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Answers:
- a. (-1, -5)
- b. up
- c. x = -1
- d.

- e. -2
- f. see attachment
- g. domain (-∞, ∞) range [-5, ∞)
<u>Explanation:</u>
f(x) = 3x² + 6x - 2
a=3 b=6 c=-2
x = 
Axis Of Symmetry: x = -1
f(-1) = 3(-1)² + 6(-1) - 2
= 3 - 6 - 2
= -5
Vertex: (-1, -5)
x = 
= 
= 
= 
= 
= 
x-intercepts: 
The domain (input values) of the cosine function is all negative and positive angle measures.
Let the function be f(x) = cos(x)
The domain of cos(x) is -∞ < x < ∞
The range is -1 ≤ f(x) ≤ 1
Hence, domain of cos(x) is all (+) and (-) angle measures.
Same goes with sine function as well
For function f(x) = sin(x)
The domain is -∞ < x < ∞ and range -1 ≤ f(x) ≤ 1
However for f(x) = tan(x) the same is not applicable.
A quadratic equation is of the format:
ax² + bx + c = 0, where a ≠ 0.
The first option is not quadratic, it is a cubic, it has highest power of 3.
The second option f (x) = 3/4 x ^2 + 2x − 5, is quadratic, that is the answer.
The third f(x) = 4/x^2 - 2/x + 1, doesn't qualify because of the 2/x.
The last f(x) = 0x^2 − 9x + 7
, doesn't qualify because of the a = 0, and the rule is that a ≠ 0.
Therefore f (x) = 3/4 x ^2 + 2x − 5 represents a quadratic function.
I hope this helps.