Answer:1.47
Explanation:
I got it correct on accelus
Answer:B. The superposition of waves from the primary source and reflected waves produced regions of constructive and destructive interference.
Explanation: Tsunami is described as several waves originating from a water body mainly an ocean caused by Large scale earth movements taking place under the sea.
Superimposition of wave is the movement of one wave on another,it can be constructive or destructive.
Constructive interference is a wave interference that take place causing the Crest of one wave to align with that of another wave leading to high amplitude.
Destructive interference is a wave interference that take place causing the Trouph of one wave to align with the crest of another wave leading to low amplitude wave.
I would say that the answer is C
Answer:
<h2>
<em>Distance</em></h2>
<em>The </em><em>length</em><em> </em><em>of </em><em>the </em><em>actual </em><em>path </em><em>travelled by </em><em>a </em><em>body </em><em>is </em><em>called </em><em>distance </em><em>travelled </em><em>by </em><em>a </em><em>body.It </em><em>is </em><em>a </em><em>scalar </em><em>Quantity.</em><em>I</em><em>t</em><em> </em><em>is </em><em>measured</em><em> </em><em>in </em><em>meter(</em><em>m)</em><em> </em><em>in </em><em>SI </em><em>system.</em>
<h2>
<em>Displacement</em></h2>
<em>The </em><em>shortest </em><em>distance</em><em> </em><em>from </em><em>initial </em><em>position</em><em> </em><em>to </em><em>the </em><em>final </em><em>position</em><em> </em><em>of </em><em>a </em><em>body </em><em>is </em><em>called </em><em>displacement</em><em> </em><em>of </em><em>the </em><em>body.It </em><em>is </em><em>a </em><em>vector</em><em> </em><em>Quantity.</em><em>I</em><em>t</em><em> </em><em> </em><em>is </em><em>measured</em><em> </em><em>in </em><em>meter(</em><em>m)</em><em> </em><em>in </em><em>SI </em><em>system.</em><em>.</em>
<em>Please </em><em>see </em><em>the </em><em>attached </em><em>picture.</em><em>.</em><em>.</em>
<em>It </em><em>is </em><em>the </em><em>example </em><em>of </em><em>distance </em><em>and </em><em>displacement.</em><em>.</em><em>.</em><em>.</em>
<em>Hope </em><em>this </em><em>helps.</em><em>.</em><em>.</em>
<em>Good </em><em>luck</em><em> on</em><em> your</em><em> assignment</em><em>.</em><em>.</em><em>.</em>
Number of times the diaphragm move back and forth is 5.59×10^4
<u>Explanation:</u>
Given data,
ω=4.6 s
we have the formula
f=ω/2π
The number of times the diaphragm moves back and forth in 4.6 s is
Number of times= ft
Number of times= ft
=(ω/2π) t
=(7.54×10^4 rad/sec)(4.6 s)/2π
Number of time=5.59×10^4
Number of times the diaphragm move back and forth is 5.59×10^4
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