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ryzh [129]
3 years ago
12

How is an echo like a reflection?

Physics
2 answers:
olasank [31]3 years ago
8 0
Yea it is, an echo bounces off of surfaces
sammy [17]3 years ago
3 0

Answer:

Echoes. An echo is a sound that is repeated because the sound waves are reflected back. Sound waves can bounce off smooth, hard objects in the same way as a rubber ball bounces off the ground. Although the direction of the sound changes, the echo sounds the same as the original sound.

Explanation:

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Hello
AysviL [449]

Answer:

The wind will blow from the higher pressure over the water to lower pressure over the land causing the sea breeze. The sea breeze strength will vary depending on the temperature difference between the land and the ocean. At night, the roles reverse. The air over the ocean is now warmer than the air over the land.

Sea breezes occur during hot, summer days because of the unequal heating rates of land and water. During the day, the land surface heats up faster than the water surface. Therefore, the air above the land is warmer than the air above the ocean. Now, recall that warmer air is lighter than cooler air.

4 0
4 years ago
How to find yield strength of a load vs deflection?
liraira [26]
Σ/ε
σ = F/A
ε = ΔL/L
F = force
A = area
L = lenght
ΔL = |old lenght - new lenght|
6 0
3 years ago
Practice report of resistance measurement with Wheatstone bridge
belka [17]

Answer: Hii

Explanation: I had a picture.. so i think this might help you.. I answered this question using this picture, so i thought same might go to u too.. Hv a look.. Good Luck..!!

Download pdf
6 0
3 years ago
What are the two key elements needed for fossilization
xenn [34]
Body Fossils and Trace Fossils.


Hope I helped and good luck with school. Bye!
3 0
4 years ago
As a rain storm passes through a region, there is an associated drop in atmospheric pressure. If the height of a mercury baromet
Pani-rosa [81]

Answer:

new atmospheric pressure is 0.9838 × 10^{5}  Pa

Explanation:

given data

height = 21.6 mm = 0.0216 m

Normal atmospheric pressure = 1.013 ✕ 10^5 Pa

density of mercury = 13.6 g/cm³

to find out

atmospheric pressure

solution

we find first height of mercury when normal pressure that is

pressure p = ρ×g×h

put here value

1.013 × 10^{5}  = 13.6 × 10³ × 9.81 × h

h =  0.759 m

so change in height Δh = 0.759 - 0.0216

new height H = 0.7374 m

so new pressure = ρ×g×H

put here value

new pressure = 13.6 × 10³ × 9.81 × 0.7374

atmospheric pressure = 98380.9584

so new atmospheric pressure is 0.9838 × 10^{5}  Pa

6 0
3 years ago
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