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valentina_108 [34]
3 years ago
8

Machines A, B, and C do the same amount of work, but they each take a different amount of time. Machine A takes more time as com

pared to machine C. Machine B takes the maximum time to do the same amount of work. Which machine expends the most power doing this work?
Physics
2 answers:
Galina-37 [17]3 years ago
8 0

Answer:

Machine C is producing maximum power

Explanation:

As we know that power is defined as rate of work done or rate of energy produced.

Power = \frac{Work}{time}

Here it is given that we have three machines A , B  and C

All three machines are doing same amount of work but the time taken by the machines is different.

Here given that maximum time is taken by machine B and then out of A and C it is given that machine A took more time than machine C.

So here we know from above relation that lesser the time more will be the power so here maximum power is due to Machine C as it is doing same work in least amount of time.

Amiraneli [1.4K]3 years ago
6 0
So power is considered as the rate of doing work. Base on the problem given, my analysis is that the machine who finish the work faster is machine C. Therefore, in order to finish the same amount of work in a short period of time you are going to expend the most power. My answer is Machine C. 
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Answer:

40J

Explanation:

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Where m = mass and

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Given mass = 20kg

v = 2m/s

K.E = 1/2 x 20 x2^2

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True or False: A chemical reaction always happens when two substances are combined. (please help fast this is a test)
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Calculate the kinetic energy of a 4.00kg object traveling at 16.0 m/s
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A flat sheet of paper of area 0.365 m2 is oriented so that the normal to the sheet is at an angle of 60 ∘ to a uniform electric
andriy [413]

Answer:

A.) 3.65 N*m²/C B) No C) 0º D) 90º

Explanation:

A) The electric flux, when the electric field is uniform across a gausssian surface, can be calculated as the dot product of the electric field vector, and the vector representing the area of the surface (normal to the surface and directed outward it by convention), as follows:

Flux = E*A*cos φ

where E = 20 N/C, A = 0.365 m², φ = 60º.

Replacing by the values, we can get the value of the electric flux, as follows:

Flux = 20 N/C* 0.365 m²*0.5 = 3.65 N*m²/C

B) While the area remains constant, and doesn't change orientation, the value of the flux will be the same, regardless the shape of the sheet.

C) When the normal to the sheet and the electric field are parallel each other, the surface will intercept the maximum number of field lines, i.e. the flux will be directly E*A*cos 0º = E*A (maximum value possible).

D) When the electric field is tangent to the surface, this means that no field lines will be intercepted by the sheet, so the flux is zero.

In this case, φ = 90º, cos φ = 0

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