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almond37 [142]
2 years ago
14

The sanctuary currently has 125 exotic fish. The average amount of the tank allotted for each fish is represented by the binomia

l (2x^2-1). Are the dimensions of the new habitat The sanctuary currently has 125 exotic fish. The average amount of the tank allotted for each fish is represented by the binomial (2x^2-1). Are the dimensions of the new habitat 6x^3 -300x^2+6480x-32400 adequate for these 125 fish? Explain. Adequate for these 125 fish? Explain.
Mathematics
1 answer:
sveta [45]2 years ago
6 0
Does anyone wanna help me with something ill give u bloxburg (from ro _blox) money if u know how to do it!And yes it’s math Oudh
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A coffee shop serves three times as many cups of regular coffee as decaffeinated coffee. If the shop serves d cups of decaffeina
galben [10]

Answer:

Number of cups of regular coffee the shop sells = 3d

Step-by-step explanation:

Let

d = cups of decaffeinated coffee

Three times as many cups of regular coffee as decaffeinated coffee.

Number of cups of regular coffee the shop sells = 3d

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How do you multiply decimals
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like regular

Step-by-step explanation:

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(HELP) A Boeing 747 airplane carries approximately 467 passengers. How many trips would it take the airplane to transport 100,00
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2 years ago
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Calculus piecewise function. ​
Kipish [7]

Part A

The notation \lim_{x \to 2^{+}}f(x) means that we're approaching x = 2 from the right hand side (aka positive side). This is known as a right hand limit.

So we could start at say x = 2.5 and get closer to 2 by getting to x = 2.4 then to x = 2.3 then 2.2, 2.1, 2.01, 2.001, etc

We don't actually arrive at x = 2 itself. We simply move closer and closer.

Since we're on the positive or right hand side of 2, this means we go with the rule involving x > 2

Therefore f(x) = (x/2) + 1

Plug in x = 2 to find that...

f(x) = (x/2) + 1

f(2) = (2/2) + 1

f(2) = 2

This shows \lim_{x \to 2^{+}}f(x) = 2

Then for the left hand limit \lim_{x \to 2^{-}}f(x), we'll involve x < 2 and we go for the first piece. So,

f(x) = 3-x

f(2) = 3-2

f(2) = 1

Therefore, \lim_{x \to 2^{-}}f(x) = 1

===============================================================

Part B

Because \lim_{x \to 2^{+}}f(x) \ne \lim_{x \to 2^{-}}f(x) this means that the limit \lim_{x \to 2}f(x) does not exist.

If you are a visual learner, check out the graph below of the piecewise function. Notice the gap or disconnect at x = 2. This can be thought of as two roads that are disconnected. There's no way for a car to go from one road to the other. Because of this disconnect, the limit doesn't exist at x = 2.

===============================================================

Part C

You'll follow the same type of steps shown in part A.

However, keep in mind that x = 4 is above x = 2, so we'll deal with x > 2 only.

So you'd only involve the second piece f(x) = (x/2) + 1

You should find that f(4) = 3, and that both left and right hand limits equal this value. The left and right hand limits approach the same y value. The limit does exist here. There are no gaps to worry about when x = 4.

===============================================================

Part D

As mentioned earlier, since \lim_{x \to 4^{+}}f(x) = \lim_{x \to 4^{-}}f(x) = 3, this means the limit \lim_{x \to 4}f(x) does exist and it's equal to 3.

As x gets closer and closer to 4, the y values are approaching 3. This applies to both directions.

4 0
1 year ago
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