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Ymorist [56]
2 years ago
6

Simplify the expression.

Mathematics
1 answer:
Ad libitum [116K]2 years ago
8 0

Answer:

-10p/3+32-3/2^p

Step-by-step explanation:

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Find exact values for sin θ, cos θ and tan θ if csc θ = 3/2 and cos θ < 0.
kumpel [21]

Answer:

Part 1) sin(\theta)=\frac{2}{3}

Par 2) cos(\theta)=-\frac{\sqrt{5}}{3}

Part 3) tan(\theta)=-\frac{2\sqrt{5}}{5}

Step-by-step explanation:

step 1

Find the sin(\theta)

we have

csc(\theta)=\frac{3}{2}

Remember that

csc(\theta)=\frac{1}{sin(\theta)}

therefore

sin(\theta)=\frac{2}{3}

step 2

Find the cos(\theta)

we know that

sin^{2}(\theta) +cos^{2}(\theta)=1

we have

sin(\theta)=\frac{2}{3}

substitute

(\frac{2}{3})^{2} +cos^{2}(\theta)=1

\frac{4}{9} +cos^{2}(\theta)=1

cos^{2}(\theta)=1-\frac{4}{9}

cos^{2}(\theta)=\frac{5}{9}

square root both sides

cos(\theta)=\pm\frac{\sqrt{5}}{3}

we have that

cos(\theta) < 0 ---> given problem

so

cos(\theta)=-\frac{\sqrt{5}}{3}

step 3

Find the tan(\theta)

we know that

tan(\theta)=\frac{sin(\theta)}{cos(\theta)}

we have

sin(\theta)=\frac{2}{3}

cos(\theta)=-\frac{\sqrt{5}}{3}

substitute

tan(\theta)=\frac{2}{3}:-\frac{\sqrt{5}}{3}=-\frac{2}{\sqrt{5}}

Simplify

tan(\theta)=-\frac{2\sqrt{5}}{5}

6 0
3 years ago
Which of the following are square roots of 265
Studentka2010 [4]

Answer:

Step-by-step explanation:

5 0
2 years ago
1.4t−0.4(t−3.1)=5.8<br><br> SOLVE FOR Y
VladimirAG [237]
There is no y in this question, however we can solve for t.

1.4t - 0.4(t - 3.1) = 5.8
1.4t - 0.4t + 1.24 = 5.8
t + 1.24 = 5.8
t = 4.56
3 0
3 years ago
Find the total lateral area of the following
maxonik [38]

Answer:

15π cm²

Step-by-step explanation:

The total lateral area of a cone

= πr√h² + r²

= √h² + r² = l

h = Height = 4cm

r = radius = 3cm

Hence:

= π × 3 √4² + 3²

= 3π × √16 + 9

= 3π × √25

= 3π × 5

= 15π cm²

7 0
2 years ago
Which of the following is equivalent to the expression below?<br> log 3-log 15
Nikitich [7]

Answer:

C. =log\frac{1}{5}

Step-by-step explanation:

Formula =======================

<em>consider a and b two real numbers </em>

<em>where a > 0 and b > 0.</em>

log\frac{a}{b} =loga-logb

……………………………………………………………

log 3 − log 15

=log\frac{3}{15}

=log\frac{3}{3\times 5}

=log\frac{1}{5}

8 0
1 year ago
Read 2 more answers
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