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2 years ago

How do you find theoretical probability?

Mathematics

1 answer:

shepuryov [24]2 years ago

4 0

Step-by-step explanation:

<h2>Theoretical Probability Definition</h2>

Theoretical probability is the theory behind probability. To find the probability of an event using theoretical probability, it is not required to conduct an experiment. Instead of that, we should know about the situation to find the probability of an event occurring. The theoretical probability is defined as the ratio of the number of favourable outcomes to the number of possible outcomes.

<h3>Find the probability of rolling a 5 on a fair die</h3>

Solution: 

To find the probability of getting 5 while rolling a die, an experiment is not needed. We know that there are 6 possible outcomes when rolling a die. They are 1, 2, 3, 4, 5, 6.Therefore, the probability is,Probability of Event P(E) = No. of. Favourable outcomes/ No. of. Possible outcomes.P(E) = 1/6.Hence, the probability of getting 5 while rolling a fair die is 1/6.

I hope it helps

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Find the vector projection of B onto A if A = 5i + 11j – 2k,B = 4i + 7k

valkas [14]

Answer:

$\frac{3}{13} i+\frac{11}{130} j-\frac{6}{65} k\\$

Step-by-step explanation:

Given A = 5i + 11j – 2k and B = 4i + 7k, the vector projection of B unto a is expressed as $proj_ab = \dfrac{b.a}{||a||^2} * a$

b.a = (5i + 11j – 2k)*( 4i + 0j + 7k)

note that i.i = j.j = k.k =1

b.a = 5(4)+11(0)-2(7)

b.a = 20-14

b.a = 6

||a|| = √5²+11²+(-2)²

||a|| = √25+121+4

||a|| = √130

square both sides

||a||² = (√130)

||a||² = 130

$proj_ab = \dfrac{6}{130} * (5i+11j-2k)\\\\proj_ab = \frac{30}{130} i+\frac{11}{130} j-\frac{12}{130} k\\\\proj_ab = \frac{3}{13} i+\frac{11}{130} j-\frac{6}{65} k\\\\$

Hence the projection of b unto a is expressed as $\frac{3}{13} i+\frac{11}{130} j-\frac{6}{65} k\\$

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3 years ago

Find g(1) if g(x) = 1x+5

Nikitich [7]

Answer:

g(1) = 6

Step-by-step explanation:

Substituting 1 into g(x):

g(1) = 1(1) + 5

= 1 + 5

= 6

Hope this helps and be sure to have a wonderful time ahead at Brainly! :D

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