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3 years ago

Please help with c Thanks ASAP

Mathematics

1 answer:

ddd [48]3 years ago

8 0

pyramid A: 16 + $8\sqrt{5$

pyramid B: 400 + $8\sqrt{125$

pyramid A: 4 by 4= 16 cm.

with a height of 1 and length of 2, we use pythagorean theorem to find height of other surfaces to be square root of 5. area of triangle is 1/2 bh

square root of 5 multiplied by 4 and divided by 2 is 2 root 5

multiply this by 4 sides total for 8 root 5

Add the 8 root 5 to 16

To find pyramid B: use ratio of 25:1 and multiply 16 by 25 to find 400, and root 5 to 125

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3 years ago

What is the following product? Assume x>/=0 ^3sqrt(x^2)*^sqrtx^3

RoseWind [281]

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$x(\sqrt[12]{x^5} )$

Step-by-step explanation:

We need to remember 2 rules when doing these:

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Using these 2 rules, we can simplify the product (steps shown below):

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7 0

3 years ago

Please help me on this!

const2013 [10]

By evaluating, we will see that for x = 7 h(x) exceeds g(x).

<h3>For which value of x does h(x) first exceed g(x)?</h3>

We have:

h(x) = 2*(2)^x

g(x) = 22x - 4

Now we can evaluate both function in the different options:

h(5) = 2*(2)^5 = 64

g(5) = 22*5 - 4 = 106

We can see that for x = 5, h(x) does not exceed g(x), let's try the next one.

h(6) = 2*(2)^6 = 128

g(6) = 22*6 - 4 = 128

So, for x = 6 both functions have the same output, then for x = 7 we will see that h(x) exceeds g(x).

The correct option is B.

If you want to learn more about functions:

brainly.com/question/4025726

#SPJ1

6 0

2 years ago