Help please ASAP!!

What is the value for "m" that makes the equation true?

Anna11 [10]

Hi I think the answer is 24 hope that’s right

3 0

3 years ago

Suppose a random sample of 200 Americans is asked to disclose whether they can order a meal in a foreign language. Describe the

taurus [48]

Answer:

The distribution of sample proportion Americans who can order a meal in a foreign language is,

$\hat p\sim N(p,\ \sqrt{\frac{p(1-p)}{n}})$

Step-by-step explanation:

According to the Central limit theorem, if from an unknown population large samples of sizes n > 30, are selected and the sample proportion for each sample is computed then the sampling distribution of sample proportion follows a Normal distribution.

The mean of this sampling distribution of sample proportion is:

$\mu_{\hat p}=p$

The standard deviation of this sampling distribution of sample proportion is:

$\sigma_{\hat p}=\sqrt{\frac{p(1-p)}{n}}$

The sample size of Americans selected to disclose whether they can order a meal in a foreign language is, n = 200.

The sample selected is quite large.

The Central limit theorem can be applied to approximate the distribution of sample proportion.

The distribution of sample proportion is,

$\hat p\sim N(p,\ \sqrt{\frac{p(1-p)}{n}})$

3 0

3 years ago

Which ordered pair is a solution to the system of linear equations 1/2x-3/4y=11/60 and 2/5x+1/6y=3/10

natka813 [3]

ANSWER

$( \frac{2}{3} , \frac{1}{5} )$

EXPLANATION

The first equation is

$\frac{1}{2} x - \frac{3}{4} y = \frac{11}{60} ...(1)$

The second equation is

$\frac{2}{5} x + \frac{1}{6} y = \frac{3}{10} ...(2)$

We want to eliminate y, so we multiply the first equation by

$\frac{4}{5}$

$\frac{4}{5} \times \frac{1}{2} x - \frac{4}{5} \times \frac{3}{4} y = \frac{11}{60} \times \frac{4}{5}$

$\frac{2}{5} x - \frac{3}{5} y = \frac{11}{75} ...(3)$

We now subtract equation (3) from (2)

$(\frac{2}{3} x - \frac{2}{3} x )+ ( \frac{1}{6} y - - \frac{3}{5}y ) =( \frac{3}{10} - \frac{11}{75} )$

$\frac{1}{6} y + \frac{3}{5}y =\frac{3}{10} - \frac{11}{75}$

$\frac{23}{30}y = \frac{23}{150}$

Multiply both sides by

$\frac{30}{23}$

$\implies \: \frac{30}{23} \times \frac{23}{30}y= \frac{23}{150} \times \frac{30}{23}$

$\implies \: y = \frac{1}{5}$

Substitute into the first equation to solve for x .

$\frac{1}{2} x - \frac{3}{4} \times \frac{1}{5} = \frac{11}{60}$

Multiply to obtain

$\frac{1}{2} x - \frac{3}{20} = \frac{11}{60}$

$\frac{1}{2} x = \frac{11}{60} + \frac{3}{20}$

$\frac{1}{2} x = \frac{1}{3}$

Multiply both sides by 2.

$2 \times \frac{1}{2} x =2 \times \frac{1}{3}$

$x = \frac{2}{3}$

The solution is

$( \frac{2}{3} , \frac{1}{5} )$

5 0

3 years ago

Read 2 more answers

I need help ASAP I have 8 minutes left

jeka57 [31]

Answer:

The answer is A

Step-by-step explanation:

Find the area of the circle = pi x radius^2

Divide the area by 4 = area of sector

4 0

3 years ago

PLEASE HELP ITS DUE NOW!!!!!! WILL MARK BRAINLIEST!!!!!

Sindrei [870]

Answer:

(- 4, - 10 )

Step-by-step explanation:

y = 5x + 10 → (1)

y = 4x + 6 → (2)

Substitute y = 5x + 10 into (2)

5x + 10 = 4x + 6 ( subtract 4x from both sides )

x + 10 = 6 ( subtract 10 from both sides )

x = - 4

Substitute x = - 4 into either of the 2 equations and evaluate for y

Substituting into (1)

y = 5(- 5) + 10 = - 20 + 10 = - 10

solution is (- 4, - 10 )

5 0

3 years ago

Read 2 more answers

Help please ASAP!! ​

Help please ASAP!!