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3 years ago

Help please ASAP!!

Mathematics

1 answer:

Natasha2012 [34]3 years ago

5 0

Both are irrational. i hope this helps!

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Simplify 4^2+6(.5)-2^

Alborosie

Following PEMDAS

Step 1: 16+6(.5)-8
Step 2:16+3-8
Step3: 19-8
Step 4:=8

————

Step 1: 10-(3+4)
Step 2: 10-(7)
Step3: =3

8 0

3 years ago

Read 2 more answers

How to compare 2 5/9 and 21/3

max2010maxim [7]

Answer:

2 5/9 is less than 21/3; 2 5/9 < 21/3

Step-by-step explanation:

Step 1: Convert 2 5/9 into an improper fraction

2 5/9 = 2 * 9/9 + 5/9 = 18/9 + 5/9 = 23/9

Step 2: Convert 21/3 so the denominator is 9

21*3 / 3*3 = 63/9

Step 3: Compare

23/9 < 63/9

Answer: 2 5/9 is less than 21/3; 2 5/9 < 21/3

5 0

3 years ago

Read 2 more answers

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brilliants [131]

Answer:

(a) x=2, y=-1

(b) x=2, y=2

(c) $\displaystyle x=\frac{5}{2}, y=\frac{5}{4}$

(d) x=-2, y=-7

Step-by-step explanation:

Cramer's Rule

It's a predetermined sequence of steps to solve a system of equations. It's a preferred technique to be implemented in automatic digital solutions because it's easy to structure and generalize.

It uses the concept of determinants, as explained below. Suppose we have a 2x2 system of equations like:

$\displaystyle \left \{ {{ax+by=p} \atop {cx+dy=q}} \right.$

We call the determinant of the system

$\Delta=\begin{vmatrix}a &b \\c &d \end{vmatrix}$

We also define:

$\Delta_x=\begin{vmatrix}p &b \\q &d \end{vmatrix}$

And

$\Delta_y=\begin{vmatrix}a &p \\c &q \end{vmatrix}$

The solution for x and y is

$\displaystyle x=\frac{\Delta_x}{\Delta}$

$\displaystyle y=\frac{\Delta_y}{\Delta}$

(a) The system to solve is

$\displaystyle \left \{ {{x+y=1} \atop {x-2y=4}} \right.$

Calculating:

$\Delta=\begin{vmatrix}1 &1 \\1 &-2 \end{vmatrix}=-2-1=-3$

$\Delta_x=\begin{vmatrix}1 &1 \\4 &-2 \end{vmatrix}=-2-4=-6$

$\Delta_y=\begin{vmatrix}1 &1 \\1 &4 \end{vmatrix}=4-3=3$

$\displaystyle x=\frac{\Delta_x}{\Delta}=\frac{-6}{-3}=2$

$\displaystyle y=\frac{\Delta_y}{\Delta}=\frac{3}{-3}=-1$

The solution is x=2, y=-1

(b) The system to solve is

$\displaystyle \left \{ {{4x-y=6} \atop {x-y=0}} \right.$

Calculating:

$\Delta=\begin{vmatrix}4 &-1 \\1 &-1 \end{vmatrix}=-4+1=-3$

$\Delta_x=\begin{vmatrix}6 &-1 \\0 &-1 \end{vmatrix}=-6-0=-6$

$\Delta_y=\begin{vmatrix}4 &6 \\1 &0 \end{vmatrix}=0-6=-6$

$\displaystyle x=\frac{\Delta_x}{\Delta}=\frac{-6}{-3}=2$

$\displaystyle y=\frac{\Delta_y}{\Delta}=\frac{-6}{-3}=2$

The solution is x=2, y=2

$\displaystyle \left \{ {{-x+2y=0} \atop {x+2y=5}} \right.$

Calculating:

$\Delta=\begin{vmatrix}-1 &2 \\1 &2 \end{vmatrix}=-2-2=-4$

$\Delta_x=\begin{vmatrix}0 &2 \\5 &2 \end{vmatrix}=0-10=-10$

$\Delta_y=\begin{vmatrix}-1 &0 \\1 &5 \end{vmatrix}=-5-0=-5$

$\displaystyle x=\frac{\Delta_x}{\Delta}=\frac{-10}{-4}=\frac{5}{2}$

$\displaystyle y=\frac{\Delta_y}{\Delta}=\frac{-5}{-4}=\frac{5}{4}$

The solution is

$\displaystyle x=\frac{5}{2}, y=\frac{5}{4}$

(d) The system to solve is

$\displaystyle \left \{ {{6x-y=-5} \atop {4x-2y=6}} \right.$

Calculating:

$\Delta=\begin{vmatrix}6 &-1 \\4 &-2 \end{vmatrix}=-12+4=-8$

$\Delta_x=\begin{vmatrix}-5 &-1 \\6 &-2 \end{vmatrix}=10+6=16$

$\Delta_y=\begin{vmatrix}6 &-5 \\4 &6 \end{vmatrix}=36+20=56$

$\displaystyle x=\frac{\Delta_x}{\Delta}=\frac{16}{-8}=-2$

$\displaystyle y=\frac{\Delta_y}{\Delta}=\frac{56}{-8}=-7$

The solution is x=-2, y=-7

4 0

3 years ago

Please help me! I will give brainliest to the best answer

8_murik_8 [283]

1. When there are two events that need to happen, we must multiply the probability of each event happening.

Shawn losing to Mike: 5/8 chance
Shawn losing to Tim: 2/7 chance

5/8 × 2/7 = 10/56 = 5/28

There's a 5/28 chance of Shawn losing to Mike and Tim.

I don't know #2, sorry :/

Hope this helps!

5 0

3 years ago

I need help on this h/j=15 for j

4vir4ik [10]

x in (-oo:+oo)

h/j = 15 // - 15

h/j-15 = 0

h*j^-1-15 = 0

x należy do R

x in (-oo:+oo)

8 0

3 years ago

Help please ASAP!! ​

Help please ASAP!!