Question

A circle has a diameter with endpoints

Answer 1

Answer:

x² + y² = 841

Step-by-step explanation:

Midpoint of diameter is a center of a circle.

Coordinates of midpoint are

( $x_{1}$ , $y_{1}$ )

( $x_{2}$ , $y_{2}$ )

( $\frac{x_{1} +x_{2} }{2}$ , $\frac{y_{1} +y_{2} }{2}$ )

d = $\sqrt{(x_{2} -x_{1})^2 +(y_{2} -y_{1})^2 }$

Equation of a circle with center at (h, k) and radius "r" is (x - h)² + (y - k)² = r²

~~~~~~~~~~

C(20, 21)

D(- 20, 21)

( $\frac{-20+20}{2}$ , $\frac{-21+21}{2}$ ) = (0, 0)

d = $\sqrt{(-20-20)^2 +(21+21)^2}$ = √3364 = 58

r = $\frac{d}{2}$ = 29

x² + y² = 29²

x² + y² = 841