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Misha Larkins [42]
3 years ago
11

Help me solve this!!! 5+ 8 % -3= *

Mathematics
1 answer:
aivan3 [116]3 years ago
4 0

Answer:

The answer would be 4 I think

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Without subtracting 8.5-4.64, determine what digit will be in the hundredths place. Explain.
Fofino [41]

Answer:

6

Step-by-step explanation:

8.5 can also be written as 8.50. If you take the digits in the hundredths place, 10 and 4, and subtract them, you get 6.

8 0
3 years ago
How to wirte a linear equation from a graph
astra-53 [7]
Hey there!
I'll assume we're using the slope-intercept form equation:
y = mx + b
m = slope
b = y-intercept
First, we keep the y, because it's value depends on the x value given.
Next, we find the slope. Slope is defined as rise/run, so we take two points on the graph, find how much taller one is from another, and how far right/left they are, put those values over each other, and we have out slope (m).
Finally, we need to determine the y-intercept, and that's as simple as seeing where the line crosses the y axis and writing down that value.
Hope this helps!
8 0
4 years ago
HELP! I WILL MARK BRAINLIEST!
jekas [21]

Answer:

A

Step-by-step explanation:

it is A

6 0
3 years ago
Prove that
Dovator [93]

Answer:

see explanation

Step-by-step explanation:

Using the trigonometric identities

secx = \frac{1}{cosx} , cosecx = \frac{1}{sinx}

cotx = \frac{cosx}{sinx} , tanx = \frac{sinx}{cosx}

Consider the left side

secA cosecA - cotA

= \frac{1}{cosA} × \frac{1}{sinA} - \frac{cosA}{sinA}

= \frac{1}{cosAsinA} - \frac{cosA}{sinA}

= \frac{1-cos^2A}{cosAsinA}

= \frac{sin^2A}{cosAsinA} ( cancel sinA on numerator/ denominator )

= \frac{sinA}{cosA}

= tanA = right side ⇒ proven

5 0
3 years ago
Kind of confused on this question, please help
Wittaler [7]

Answer:

4th option

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

y = \frac{3}{5} x - 6 ← is in slope- intercept form

with slope m = \frac{3}{5}

Given a line with slope m then the slope of a line perpendicular to it is

m_{perpendicular} = - \frac{1}{m} = - \frac{1}{\frac{3}{5} } = - \frac{5}{3}

The equation of a line in point- slope form is

y - b = m(x - a)

where m is the slope and (a, b) a point on the line

Here m = - \frac{5}{3} and (a, b ) = (- 2, 5 ) , then

y - 5 = - \frac{5}{3} (x - (- 2) ) , that is

y - 5 = - \frac{5}{3} (x + 2)

8 0
3 years ago
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