I’m pretty sure that they are
The distance between the two schools on the map is (C) 4.2 inches.
<h3>
What is the distance?</h3>
- Distance is a numerical measurement of the distance between two objects or places.
- The distance can refer to a physical length or an estimate based on other criteria in physics or common usage.
- The distance between two points A and B is commonly expressed as |AB|.
To find the distance:
On the map,2 inches represents 5 miles.
Thus, we can write:
- 2 miles = 2 inches
- 1 mile = 2/5 inches ..... (1)
Since the actual distance between the two schools is 10.6 miles.
Multiplying both sides by 10.6 in equation (1).
- 10.6 miles = 10.6 × 2/5 = 21.2/5 = 4.24 inches.
Therefore, the distance between the two schools on the map is (C) 4.2 inches.
Know more about distance here:
brainly.com/question/17273444
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The complete question is given below:
Kim is drawing a map of the different schools in her school district. she knows that her middle school is 10.6 miles away from the middle school that her best friend attends. if every 2 inches on the map represents 5 miles, how far apart will the two schools be on the map, to the nearest tenth of an inch?
(A) 0.2 inch
(B) 0.9 inch
(C) 4.2 inches
(D) 26.5 inches
Answer:
Step-by-step explanation:
<u>Sum up the bills:</u>
- 85.40 + 125.00 + 92.60 + 155.50 = 458.5
<u>Find 12% of the sum:</u>
Answer:
I believe the answer is d
=
32
Step-by-step explanation:
You should isolate the radical, then raise each side of the equation to the power of its index.
Answer:
42.22% probability that the weight is between 31 and 35 pounds
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean and standard deviation , the zscore of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:
What is the probability that the weight is between 31 and 35 pounds
This is the pvalue of Z when X = 35 subtracted by the pvalue of Z when X = 31. So
X = 35
has a pvalue of 0.5557
X = 31
has a pvalue of 0.1335
0.5557 - 0.1335 = 0.4222
42.22% probability that the weight is between 31 and 35 pounds