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attashe74 [19]
3 years ago
12

Find values of x, HJ, and JK.​

Mathematics
1 answer:
xz_007 [3.2K]3 years ago
5 0

Answer:

x = 2, HJ = JK = 11

Step-by-step explanation:

Given that H is the midpoint of JK , then

HJ = JK = 6x - 1 and

HJ + JK = JK , that is

6x - 1 + 6x - 1 = 3x + 16 ← simplify left side

12x - 2 = 3x + 16 ( subtract 3x from both sides )

9x - 2 = 16 ( add 2 to both sides )

9x = 18 ( divide both sides by 9 )

x = 2

Then

HJ = JK = 6x - 1 = 6(2) - 1 = 12 - 1 = 11

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Answer:

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Step-by-step explanation:

Use the distance formula:

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3 years ago
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Answer:

Step-by-step explanation:

Given:

Type of Flowers = 5

To choose = 4

Required

Number of ways 4 can be chosen

The first flower can be chosen in 5 ways

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The third flower can be chosen in 3 ways

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Total Number of Selection = 5 * 4 * 3 * 2

Total Number of Selection = 120 ways;

Alternatively, this can be solved using concept of Permutation;

Given that 4 flowers to be chosen from 5,

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Such that

nPr = \frac{n!}{(n - r)!}

Substitute 5 for n and 4 for r

5P4 = \frac{5!}{(5 - 4)!}

5P4 = \frac{5!}{1!}

5P4 = \frac{5*4*3*2*1}{1}

5P4 = \frac{120}{1}

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Hence, the number of ways the florist can chose 4 flowers from 5 is 120 ways

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3 years ago
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Answer:

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