Answer:
The surface area of the cube is 648.96 sq in.
Step-by-step explanation:
This problem is made a lot easier by the fact that it's a cube.
So we first calculate the area of one of the faces. The length of the side of the side is 10.4 inches, and <em>10.4 * 10.4 = 100.16.</em>
There are six faces, so we multiply the area of 1 face by 6. <em>100.16 * 6 = 648.96. </em>
Therefore, the surface area of the cube is 648.96 sq inches.
<em>Hope This Helps!</em>
X,y - two numbers (x > y)
(1) x + y = 67 ⇒ x = 67 - y
(2) x - 4 = 2y
subtitute (1) to (2)
67 - y - 4 = 2y
63 - y = 2y |add y to both sides
63 = 3y |divide both sides by 3
y = 21
subtitute the value of y to (1)
x = 67 - 21 = 46
Answer: 21 and 46.
Answer:
3:15
Step-by-step explanation:
Answer:
Probability that the diameter of a selected bearing is greater than 111 millimeters is 0.1056.
Step-by-step explanation:
We are given that the diameters of ball bearings are distributed normally. The mean diameter is 106 millimeters and the standard deviation is 4 millimeters.
<em>Firstly, Let X = diameters of ball bearings</em>
The z score probability distribution for is given by;
Z =
~ N(0,1)
where,
= mean diameter = 106 millimeters
= standard deviation = 4 millimeter
Probability that the diameter of a selected bearing is greater than 111 millimeters is given by = P(X > 111 millimeters)
P(X > 111) = P(
>
) = P(Z > 1.25) = 1 - P(Z
1.25)
= 1 - 0.89435 = 0.1056
Therefore, probability that the diameter of a selected bearing is greater than 111 millimeters is 0.1056.
C. Y = 3/10x + 1/2
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