Check the picture below.
now, notice, for the angle hAC, the hypotenuse is hA, and the adjacent side is CA, therefore,
![\bf cos(\theta)=\cfrac{adjacent}{hypotenuse}\qquad cos(hAC)=\cfrac{5}{hA}\implies hA=\cfrac{5}{cos(hAC)} \\\\\\ hA=\cfrac{5}{cos\left[ \frac{cos^{-1}\left( \frac{5}{13} \right)}{2} \right]}](https://tex.z-dn.net/?f=%5Cbf%20cos%28%5Ctheta%29%3D%5Ccfrac%7Badjacent%7D%7Bhypotenuse%7D%5Cqquad%20cos%28hAC%29%3D%5Ccfrac%7B5%7D%7BhA%7D%5Cimplies%20hA%3D%5Ccfrac%7B5%7D%7Bcos%28hAC%29%7D%0A%5C%5C%5C%5C%5C%5C%0AhA%3D%5Ccfrac%7B5%7D%7Bcos%5Cleft%5B%20%5Cfrac%7Bcos%5E%7B-1%7D%5Cleft%28%20%5Cfrac%7B5%7D%7B13%7D%20%5Cright%29%7D%7B2%7D%20%5Cright%5D%7D)
make sure your calculator is in Degree mode, if you need the angle in degrees.
Let, the number = x
8x-10 ≥ 6x+14
Subtracting 6x form both sides,
2x-10 ≥ 14
Adding 10 to both sides,
2x ≥ 24
Dividing by 2,
x ≥ 12
- Please see the attached picture for full solution!:)
------------- HappY LearninG <3 ---------
We call a full circle or a full rotation 360 degrees. There's nothing magic
or mathematical about that number. It was invented by people. It could
have been any number they wanted.
But it was a great choice because it has a lot of factors. With 360 degrees
in a full rotation, you can split up a full rotation into 2, 3, 4, 5, 6, 8, 9, 10, 12,
15, 18, 20, 24, 30, 36, 40, 45, 60, 72, 90, 120, or 180 equal pieces, without
ever slicing up a degree !
