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3 years ago

What is the value of x in the following system Y=3x-5 and 6x+3y=15

Mathematics

1 answer:

beks73 [17]3 years ago

7 0

Answer:

hope this helped

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Which expression is equivalent to 8? -48 ÷ 6 48 ÷ (-6) 48 ÷ 6 -48 ÷ (-6)

V125BC [204]

Expression 3,
because 6 and 8 are factors of 48. Since positive 6 & 8 are the two numbers of choice, the product will be positive. My answer is reasonable because if you were to multiply positive 8 and 6 you will get positive 48.

8 0

3 years ago

How

Lady_Fox [76]

Your mom is 65. uh huh

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2 years ago

A ball is thrown from an initial height of 2 meters with an initial upward velocity of 9/ms . The ball's height h (in meters) af

Alecsey [184]

A ball is thrown from an initial height of 2 meters with an initial upward velocity of 9/ms

Balls height $h= 2 +9t -5t^2$

To find all values of t for which the ball's height is 3 meters

We plug in 3 for h and solve for t

$h= 2 +9t -5t^2$

$3 = 2 +9t -5t^2$

Solve for t

$0= -1+ 9t -5t^2$

$5t^2 - 9t + 1 = 0$

Solve using quadratic formula

$t= \frac{-b+- \sqrt{b^2-4ac} }{2a}$

$t= \frac{9+- \sqrt{(-9)^2-4*5*1} }{2*5}$

After simplifying this,

$t= \frac{9+\sqrt{61}}{10}$ = 0.11898

$t= \frac{9-\sqrt{61}}{10}$ = 1.68102

the values of t for which the ball's height is 3 meters= 0.12 sec , 1.68 sec

5 0

3 years ago

I really need help with this Triangle problem.

julia-pushkina [17]

Answer:

x = 10

y = 20

Step-by-step explanation:

$\tan \: 30 \degree = \frac{x}{10 \sqrt{3} } \\ \\ \frac{1}{ \sqrt{3} } = \frac{x}{10 \sqrt{3} } \\ \\ \sqrt{3} x = 10 \sqrt{3} \\ \\ x = \frac{10 \sqrt{3} }{ \sqrt{3} } \\ \\ x = 10 \\ \\ \cos 30 \degree = \frac{10 \sqrt{3} }{y} \\ \\ \frac{ \sqrt{3} }{2} = \frac{10 \sqrt{3} }{y} \\ \\ y = 10 \sqrt{3} \times \frac{2}{ \sqrt{3} } \\ \\ y = 10 \times 2 \\ \\ y = 20$