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k0ka [10]
3 years ago
11

Find the volume of the composite solid. Round your anwser to the nearest hundredth.

Mathematics
1 answer:
Lelu [443]3 years ago
6 0

Answer:

226.19 cm^{3}

Step-by-step explanation:

Vol. of cone = Bh/3   where B is the area of the base(circle) and h is the height of the cone.

r = 3   h = 3

V = \frac{\pi *3^{2}*3 }{3} = 9π

Vol. of the cylinder = Bh   where B is the base(circle) and h is the height of the cylinder.

r = 3   h = 10 - 3 = 7

V = \pi *3^{2} * 7 = 63π

Total volume = 9π + 63π = 72π = 72(3.1416....) = 226.19

 

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Answer:

Step-by-step explanation:

The angle we are given is 2° and we are given the opposite leg, 135 ft. We are trying to find the hypotenuse length- the diagonal distance from the ship to the lighthouse.

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3 years ago
What’s the 5th term is 2,14,98
iragen [17]

\bold{\huge{\orange{\underline{ Solution }}}}

<h3><u>Correct </u><u>Question </u><u>:</u><u>-</u></h3>

What is the 5th term of an AP 2 , 14 ....98 .

<h3><u>Given </u><u>:</u><u>-</u><u> </u></h3>

<u>We </u><u>have </u><u> </u><u>AP</u><u>, </u>

  • \sf{ 2 , 14 ,.... 98 }
  • <u>AP </u><u>is </u><u>the </u><u>arithmetic </u><u>progression </u><u>or </u><u>a </u><u>sequence </u><u>of </u><u>numbers </u><u>in </u><u>which </u><u>succeeding </u><u>number </u><u>is </u><u>differ </u><u>from </u><u>preceeding </u><u>number </u><u>by </u><u>a </u><u>common </u><u>value</u><u>. </u>

<h3><u>Solution </u><u>:</u><u>-</u></h3>

<u>We </u><u>have </u><u>an </u><u>AP </u><u>:</u><u>-</u><u> </u><u>2</u><u> </u><u>,</u><u> </u><u>1</u><u>4</u><u> </u><u>.</u><u>.</u><u>.</u><u>.</u><u>.</u><u>9</u><u>8</u>

<u>Therefore</u><u>, </u>

  • \sf{a1\: or \:1st\: term = 2 }
  • \sf{a2 \:or \:2nd\: term = 14 }
  • \sf{an \:or\: last\: term = 98}

<u>Here</u><u>, </u>

Common difference of an AP

\sf{ a2 - a1 }

\sf{ = 14 - 2}

\sf{ = 12}

Thus, The common difference is 12

<u>Now</u><u>, </u>

We know that,

\sf{an = a1 + ( n - 1 )d}

\sf{a5 = 2 + ( 5 - 1 )12}

\sf{a5 = 2 + 4 × 12}

\sf{a5 = 2 + 48}

\sf{\red{a5 = 50}}

Hence, The 5th term of given AP is 50

4 0
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Answer:

the average speed of the car is:

b. 0.75

an equation of the line is:

b. n-6= 0.75(t-8)

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