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maksim [4K]
3 years ago
15

Can anyone help me with this?? giving brainly..

Mathematics
1 answer:
Black_prince [1.1K]3 years ago
6 0

Answer:

Multiply the height and the width!!

Step-by-step explanation:

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A 3 foot wide painting should be centered on 13 foot wide wall how many feet should be on each side of the painting
VLD [36.1K]

Answer:

5 feet of wall should be on each side of the painting.

Step-by-step explanation:

Given that a 3 foot wide painting should be centered on 13 foot wide wall, to determine how many feet should be on each side of the painting, the following calculations must be performed:

(13 - 3) / 2 = X

10/2 = X

5 = X

Therefore, 5 feet of wall should be on each side of the painting.

5 0
3 years ago
Solve this problem, and identify the percent, amount, and base.<br> What percent of 60 is 15?
ValentinkaMS [17]
First, you must understand the question. what % of 60 is 15, so I would write an equation to express this.

15 = 60x

From there, solve for x, so Divide by 60 on each side. The answer is 1/4, or 25%
7 0
4 years ago
5k race surveyed runners about their finishing times (f) and the number of previous races they had run (n). The organizers found
vichka [17]
I FOUND YOUR COMPLETE QUESTION IN OTHER SOURCES.
 
SEE ATTACHED IMAGE, PLEASE.
 
The first thing we must do for this case is to define variables.
 n = number of 5k races covered
 f = end time.
 We have the following equation:
 f = -1.2n + 38.1
 We note that the slope of the line is:
 m = -1.2 minutes per race
 Therefore, the time decreases 1.2 minutes when the number of races increases n.
 Answer:
 
The model predicts that for each additional race to runner has run, the finishing time decreases by about 1.2 minutes

3 0
3 years ago
100 points and brainliest for correct answer!
dusya [7]
City C (42 and 66 are the two modes they are the most frequent numbers both appearing 3 times)
4 0
2 years ago
Helppppppp pleaseeee it’s mathhhhhh
Anuta_ua [19.1K]

Answer:

73

Step-by-step explanation:

6x+25=10x-11

-4x=-36

x=8

6(8)+25

48+25=73

I am not sure on this one but hope I helped

3 0
3 years ago
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