Answer:
y2 = (6x + 7)/36 + (Dx + E)e^x
Step-by-step explanation:
The method of reduction of order is applicable for second-order differential equations.
For a known solution y1 of a 2nd order differential equation, this method assumes a second solution in the form Uy1 which satisfies the said differential equation. It then assumes a reduced order for U'' (w' = U'').
The differential equation becomes easy to solve, and all that is left are integration and substitutions.
Check attachments for the solution to this problem.
For this case we subtract $228 minus $12 to find the amount of money Tim spent on books. So, to know how much spending in each book we divide $228 by 6.
So, we have that each book costs $38.
Answer:
Each book costs $38
Answer:
a) Statement is true
b) Statement incorrect. Company goal is to attend customer at 190 second at the most. So test should be one tail test (right)
c) We have to reject H₀, and differences between sample mean and the hypothesized population mean should not be attributed only to sampling error
Step-by-step explanation:
a) as the significance level is = 0,02 that means α = 0,02 (the chance of error type I ) and the β (chance of type error II is
1 - 0.02 = 0,98
b) The company establishe in 190 seconds time for customer at its ticket counter (if this time is smaller is excellent ) company is concerned about bigger time because that could be an issue for customers. Therefore the test should be a one test-tail to the right
c) test statistic
Hypothesis test should be:
null hypothesis H₀ = 190
alternative hypothesis H₀ > 190
t(s) = ( μ - μ₀ ) / s/√n ⇒ t(s) = ( 202 - 190 )/(28/√100 )
t(s) = 12*10/28
t(s) = 4.286
That value is far away of any of the values found for 99 degree of fredom and between α ( 0,025 and 0,01 ). We have to reject H₀, and differences between sample mean and the hypothesized population mean should not be attributed only to sampling error
If we look table t-student we will find that for 99 degree of freedom and α = 0.02.
Answer:
a ) x = - 3, y = 5
x = 0, y = 2
x = 5, y = - 3
b ) you should draw the line by marking the coordinates in the graph, then draw a straight line passing through all those three points.
Step-by-step explanation:
y = 2 - x
When x = - 3,
y = 2 - x
= 2 - ( - 3 )
= 2 + 5
y = 7
When x = 0,
y = 2 - x
= 2 - 0
y = 2
When x = 5,
y = 2 - x
= 2 - 5
y = - 3
b ) you should draw the line by marking the coordinates in the graph, then draw a straight line passing through all those three points.
I found 50, making a rule of three where
40__10
x___25
x=10
40+10= 50
( I hope I'm right, but from what I understand this would be the resolution)
