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1 year ago

100 points and brainliest for correct answer!

Mathematics

1 answer:

dusya [7]1 year ago

4 0

City C (42 and 66 are the two modes they are the most frequent numbers both appearing 3 times)

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Example of non-statistical question , statistical question

Aleks04 [339]

Answer: A non-statistical For example, the question, 'What is 2 plus 2?' is a non-statistical question. This question has only one correct answer that doesn't change

A statistical question For example, there will likely be variability in the data collected to answer the question, "How much do the animals at Fancy Farm weigh?"

hoped this helped

4 0

2 years ago

A rectangular room room with a length of 16 feet, a width of 14 feet, and a height of 10 feet. What is the volume of the room

patriot [66]

V=LWH (multiply the length, width and height)
So plug in the numbers, V=6x14x10=840 ft^3 (feet cube)

7 0

2 years ago

Show your work plzz :))))

ankoles [38]

Answer:

9/10

Step-by-step explanation:

1/6 hour for 3/20 of his yard

6/6 hour or 1 hour = 6* 3/20 = 9/10 of his yard per hour

Mark as brainliest if this helped

6 0

2 years ago

Read 2 more answers

A bakery uses 8 tablespoons of honey for every 10 cups of flour to make bread dough. Some days they bake bigger batches and some

Tamiku [17]

Your answer: A bakery uses 8 tablespoons of honey for every 10 cups of flour to make bread dough. Some days they bake bigger batches ... brainly.com/question/18026512

7 0

1 year ago

3y''-6y'+6y=e*x sexcx

Simora [160]

From the homogeneous part of the ODE, we can get two fundamental solutions. The characteristic equation is

$3r^2-6r+6=0\iff r^2-2r+2=0$

which has roots at $r=1\pm i$ . This admits the two fundamental solutions

$y_1=e^x\cos x$
$y_2=e^x\sin x$

The particular solution is easiest to obtain via variation of parameters. We're looking for a solution of the form

$y_p=u_1y_1+u_2y_2$

where

$u_1=-\displaystyle\frac13\int\frac{y_2e^x\sec x}{W(y_1,y_2)}\,\mathrm dx$
$u_2=\displaystyle\frac13\int\frac{y_1e^x\sec x}{W(y_1,y_2)}\,\mathrm dx$

and $W(y_1,y_2)$ is the Wronskian of the fundamental solutions. We have

$W(e^x\cos x,e^x\sin x)=\begin{vmatrix}e^x\cos x&e^x\sin x\\e^x(\cos x-\sin x)&e^x(\cos x+\sin x)\end{vmatrix}=e^{2x}$

and so

$u_1=-\displaystyle\frac13\int\frac{e^{2x}\sin x\sec x}{e^{2x}}\,\mathrm dx=-\int\tan x\,\mathrm dx$
$u_1=\dfrac13\ln|\cos x|$

$u_2=\displaystyle\frac13\int\frac{e^{2x}\cos x\sec x}{e^{2x}}\,\mathrm dx=\int\mathrm dx$
$u_2=\dfrac13x$

Therefore the particular solution is

$y_p=\dfrac13e^x\cos x\ln|\cos x|+\dfrac13xe^x\sin x$

so that the general solution to the ODE is

$y=C_1e^x\cos x+C_2e^x\sin x+\dfrac13e^x\cos x\ln|\cos x|+\dfrac13xe^x\sin x$

7 0

2 years ago