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solniwko [45]
3 years ago
5

Kelvin has a string of length 4.15m. He wants to form equilateral triangles of sides 8 cm using the string . What is the maximum

number of such equilateral triangles that he can make with the string .
Mathematics
1 answer:
Fofino [41]3 years ago
5 0

4.15 meters = 415 centimeters

3(8x) = 415 (3 sides times 8 cm - amount each triangle takes)

24x = 415

x = 17.2917

The maxinum number of triangles he can make is 17.
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Brandon rolls a six sided die twenty times, and records the result in the table below. how many times did brandon roll above the
Radda [10]

The average is the arithmetic mean of all the observations of a set of numbers. The number of times Brandon rolls above the average is 7.

<h3>What is average?</h3>

The average is the arithmetic mean of all the observations of a set of numbers. it is found by dividing the sum of all the observations of the set by the number of observations in the set.

\rm{Average=\dfrac{Sum\ of\ observations}{Number\ of\ observations}

In order to know the number of times Brandon rolls the dice above the average, we first need to calculate the average of the twenty rolls.

The average of the 20 times dice rolls,

\rm Average = \dfrac{6+1+3+4+4+4+6+5+5+3+6+4+4+5+2+3+5+4+4+2}{20}

\rm Average = \dfrac{80}{20} = 4

Thus, the average of the 20 rolls of the dice is 4.

Now, the number of times the result of the dice roll is above 4(x>4) is 7.

Hence, the number of times Brandon rolls above the average is 7.

Learn more about Average:

brainly.com/question/2426692

8 0
2 years ago
I’m confused on what’s going on here, so if someone could explain it I would be super grateful.
pshichka [43]
<h2>Range of x </h2><h3>-\frac{1}{5} and x>6</h3><h3>Step-by-step explanation:</h3>

Given AB = 4x + 5, BC = 3x - 2 and AC 9x -5

The sum of the length of any two sides of a triangle is greater than the length of third side.

Case I

AB + BC > AC

⇔4x +5 +3x -2 > 9x -5

⇔7x + 3 >9x - 5

⇔ 7x -9x > -5 -3

⇔-2x > -8

⇔x <4

Case II

if AB+AC > BC

4x +5 +9x -5> 3x -2

⇔13x >3x -2

⇔ 13x -3x> -2

⇔10x > -2

⇔x >-\frac{1}{5}

Case III

AC+BC > AB

⇔9x - 5 +3x - 2 > 4x +5

⇔6x -7 > 4x +5

⇔6x -4x >5+7

⇔2x > 12

⇔x > 6

8 0
3 years ago
Write in slope intercept form . y+4=−12(x−2)
inna [77]

Answer:

20

Step-by-step explanation:

y+4=−12(x−2)

Step 1: Add -4 to both sides.

y+4+−4=−12x+24+−4

y=−12x+20

6 0
3 years ago
Read 2 more answers
Check my answer?
8_murik_8 [283]
B. Compare independent variables
4 0
3 years ago
3x+2y=10<br> 12x+5y=25<br><br> Solve by substitution or elimination
zaharov [31]
3x + 2y = 10 ....multiply by -4
12x + 5y = 25
-------------------
-12x - 8y = -40 (result of multiplying by -4)
12x + 5y = 25
------------------add
-3y = - 15
y = -15/-3
y = 5

3x + 2y = 10
3x + 2(5) = 10
3x + 10 = 10
3x = 10 - 10
3x = 0
x = 0

solution is (0,5)
5 0
3 years ago
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