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MissTica
2 years ago
8

What Made Gandhi's Nonviolent Movement Work?

Mathematics
1 answer:
nekit [7.7K]2 years ago
8 0

Answer:

Gandhi's nonviolent movement worked because Gandhi wanted to be treated equally like his protesters.  Gandhi's nonviolence worked because when he found out about this he requested that he should be sentenced even longer than the protesters.

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please help! this assgiment was due like a week ago and i’m missing so many more i just need help finishing this!
mariarad [96]

Answer:

17.5hrs

Step-by-step explanation:

Set they worked for x hours,

10x+35=210

10x=175

x=17.5

6 0
2 years ago
Consider the volume of the region shown below, which shows a right circular cone with top radius 3 cm and height 10 cm. We have
koban [17]
I have the same problem here with a slight change in the given values:

radius is 2 & height of 6 indicates the bounding line is y = 3 x---> x = y / 3.... 

<span>thus the [ π radius ² thickness ] yields π (y² / 9 ) <span>dy ,</span> y in [ 0 , 6 ] for the volume... </span>

a Riemann sum is then : y_i = 0 + i [ 6 / n ] = 6 i / n , i = 1,2,3...n and do a right side sum 

<span>π Σ { i = 1,2,3..n } [ 36 i² / 9 n² ] [ 6 / n ]
</span>
I hope my guide has come to your help. God bless and have a nice day ahead!
5 0
3 years ago
A sign in front of a roller coaster says you must be 40 inches tall to ride. What percentage of this height 34 inches?
weeeeeb [17]

Answer:

Step-by-step explanation:

Percentage of A

34/40 x 100 = 85%

Percentage of B

54/40 x 100 = 135%

Ans: A) 85% B) 135%

6 0
3 years ago
Read 2 more answers
Pls help with Trigonometric
Sav [38]

The value of the given trigonometry function is 2√15/15

<h3>Half angles</h3>

Half angles are trigonometric identities used to express sine, cosine and tangent of half angles.

For instance the value of cos theta is expressed as shown below;

cosФ = cos(Ф/2+Ф/2)

cosФ = cos²Ф/2-sin²Ф/2
cosФ = cos²Ф/2-(1-cos²Ф/2)
cosФ  = 1 - 2cos²Ф/2

Given the following parameters

cosФ = -7/15

Substitute

cosФ  = 1 - 2cos²Ф/2

-7/15  = 1 - 2cos²Ф/2

-2cos²Ф/2 = -7/15 - 1

-2cos²Ф/2 = -8/15

cos²Ф/2 = 4/15
cosФ/2 = 2/√15

Rationalize

2/√15 * √15/√15

2√15/15

Hence the value of the given trigonometry function is 2√15/15

Learn more on trigonometry function here: brainly.com/question/2254074

#SPJ1

8 0
1 year ago
Let us suppose we have data on the absorbency of paper towels that were produced by two different manufacturing processes. From
maksim [4K]

Answer:

The 95% CI for the difference of means is:

-155.45 \leq \mu_1-\mu_2 \leq -44.55

Step-by-step explanation:

<em>The question is incomplete:</em>

<em>"Find a 95% confidence interval on the difference of the towels mean absorbency produced by the two processes. Assumed that the standard deviations are estimated from the data. Round to two decimals places."</em>

Process 1:

- Sample size: 10

- Mean: 200

- S.D.: 15

Process 2:

- Sample size:  4

- Mean: 300

- S.D.: 50

The difference of the sample means is:

M_d=M_1-M_2=200-300=-100

The standard deviation can be estimated as:

\sigma_d=\sqrt{\frac{\sigma_1^2}{n_1}+\frac{\sigma_2^2}{n_2}}\\\\\sigma_d=\sqrt{\frac{15^2}{10}+\frac{50^2}{4}} =\sqrt{22.5+625}=\sqrt{647.5}=25.45

The degrees of freedom are:

df=n_1+n_2-2=10+4-2=12

The t-value for a 95% confidence interval and 12 degrees of freedom is t=±2.179.

Then, the confidence interval can be written as:

M_d-t\cdot \sigma_d\leq \mu_1-\mu_2 \leq M_d+t\cdot \sigma_d\\\\-100-2.179*25.45\leq \mu_1-\mu_2 \leq -100+2.179*25.45\\\\-100-55.45 \leq \mu_1-\mu_2 \leq -100+55.45\\\\ -155.45 \leq \mu_1-\mu_2 \leq -44.55

8 0
3 years ago
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