Question

Can some answer this math question

Answer 1

Answer:

A

Step-by-step explanation:

To multiply powers of a variable, add the exponents:

$x^m\cdot x^n = x^{m+n}$

This rule works for all exponents, positive, negative, or zero.  Also, remember that $x^0=1$.

Also, remember the definition of negative exponent:  $x^{-n} = \frac{1}{x^n}$

To multiply the two monomials, start by multiplying the coefficients, 14 and 4.  That gives 56, so your answer begins with 56.

Now for the powers of x,  $(x^3)(x^{-5}) = x^{3+(-5)} =x^{-2} = \frac{1}{x^2}$

For the powers of y,  $(y^{-4})(y^4)=y^{4+(-4)} = y^0 = 1$$(y^{-4})(y^4) = y^{-4+4} = y^0 =1$

Your answer is

$56 \cdot \frac{1}{x^2} \cdot 1 =\frac{56}{x^2}$