Let us calculate the median; the 6th observation is 20, so it is 20. We need the 6th observation so that out of the 11 observations we have 5 above the median and 5 below (or equal). We also have that then Q1 is the median of the lowest 5 observations, hence 19 (14,16,19,19,20, the 3rd observation is 19). Similarly, we get that the median for the upper half of the observations, Q3 namely, is 22 (21,21,22,22,23, the 3rd observation is 22). Thus, the interquartile range is 3=Q3-Q1. According to our calculations, all observations are wrong.
The answer to this equation is 1/2
we are given
Firstly , we can distribute
now, we can combine like terms
now, we can solve for x
and we get
...........Answer
The answer is letteer C. You just have to multiply 9 and pi
1.) X=-2
2.) 2x-y+4=0
Hope this helps! :))
