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jeka57 [31]
3 years ago
15

Find the value of a and b when a+b = -5, ab = -24​

Mathematics
2 answers:
Olin [163]3 years ago
8 0

Answer:

see explanation

Step-by-step explanation:

Given the 2 equations

a + b = - 5 → (1)

ab = - 24 → (2)

Rearranging (1) expressing a in terms of b, that is

a = - 5 - b → (3)

Substitute a = - 5 - b into (2)

b(- 5 - b) = - 24 ← distribute left side

- 5b - b² = - 24 ( subtract - 5b - b² from both sides )

0 = b² + 5b - 24 ← in standard form

0 = (b + 8)(b - 3) ← in factored form

Equate each factor to zero and solve for b

b + 8 = 0 ⇒ b = - 8

b - 3 = 0 ⇒ b = 3

Substitute these values into (3) for corresponding values of a

b = - 8 : a = - 5 - (- 8) = - 5 + 8 = 3

b = 3 : a = - 5 - 3 = - 8

Thus

a = 3, b= - 8 or a = - 8, b = 3

Serga [27]3 years ago
3 0

Step-by-step explanation:

a= - 5 - b

Subs. the above into...

ab = - 24

(-5-b)b = - 24

Therefore b=-24 or b=19

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3 years ago
A 2X2 square is centered at the origin. It is dilated by a factor of 3. What are coordinates of the vertices of the square?
Vesna [10]

Answer:

The vertices are:

A' = (-3, -3)

B' = (3, -3)

C' = (3, 3)

D' = (-3, 3)

Step-by-step explanation:

Given:

A 2 x 2 square is centered at the origin.

So, the center of the square is (0, 0)

Since it is 2 x 2 square, the side of the square is 2 units.

So, the vertices of the 2 x 2 square are A (-1, -1),  B(1, -1), C(1. 1), D(-1, 1)

The above square is dilated by a factor of 3.

Let's name the dilated square A'B'C'D'

To find the coordinates of the vertices of dilated square, we need to multiply each vertices of ABCD by 3.

A(-1, -1) = 3(-1, -1) = A'(-3, -3)

B(1, -1) = 3(1, -1) = B'(3, -3)

C(1, 1) = 3(1, 1) = C'(3, 3)

D(-1, 1) = 3(-1, 1) = D'(-3, 3)

7 0
3 years ago
Solve the formula d = st for s
Delvig [45]

Answer: s = \frac{d}{t}

Step-by-step explanation:

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7 0
3 years ago
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shutvik [7]

Answer:

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:}

8 0
3 years ago
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Bumek [7]

Answer:

6

Step-by-step explanation:

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3 0
3 years ago
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