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jeka57 [31]
2 years ago
15

Find the value of a and b when a+b = -5, ab = -24​

Mathematics
2 answers:
Olin [163]2 years ago
8 0

Answer:

see explanation

Step-by-step explanation:

Given the 2 equations

a + b = - 5 → (1)

ab = - 24 → (2)

Rearranging (1) expressing a in terms of b, that is

a = - 5 - b → (3)

Substitute a = - 5 - b into (2)

b(- 5 - b) = - 24 ← distribute left side

- 5b - b² = - 24 ( subtract - 5b - b² from both sides )

0 = b² + 5b - 24 ← in standard form

0 = (b + 8)(b - 3) ← in factored form

Equate each factor to zero and solve for b

b + 8 = 0 ⇒ b = - 8

b - 3 = 0 ⇒ b = 3

Substitute these values into (3) for corresponding values of a

b = - 8 : a = - 5 - (- 8) = - 5 + 8 = 3

b = 3 : a = - 5 - 3 = - 8

Thus

a = 3, b= - 8 or a = - 8, b = 3

Serga [27]2 years ago
3 0

Step-by-step explanation:

a= - 5 - b

Subs. the above into...

ab = - 24

(-5-b)b = - 24

Therefore b=-24 or b=19

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Scrat [10]

Answer:19, 81, 45

Step-by-step explanation:

7 0
3 years ago
Find the equation of the line that contains the point (4,-2) and is perpendicular to the line y=-2x+8.
snow_tiger [21]

Answer:

\frac{1}{2} x - 4

Step-by-step explanation:

Perpendicular lines will have slopes that are the multiplicative additive inverse of each other: a line with slope 3/4 is perpendicular to a line with slope -4/3, for example.  You need a line that is perpendicular to a line with slope -2 (reading that from the -2 in the -2x portion of the given equation, which is written in slope-intercept form), so your new line must have slope +1/2.

With the slope and a point, we can come up with an equation using this formula:

y - y-coordinate = slope (x - x-coordinate)

So we have y - (-2) = 1/2 (x - 4).

Simplify the equation:  y + 2 = 1/2 x - 2

Subtract 2 from both sides: y + 2 - 2 = 1/2 x - 2 - 2

Simplify: y = 1/2 x - 4.

4 0
2 years ago
What are the exact solutions of x2 − 5x − 7 = 0, where x equals negative b plus or minus the square root of b squared minus 4 ti
Marat540 [252]

Answer:

x = \frac{5 + \sqrt{53}}{2}  or  x = \frac{5 - \sqrt{53}}{2}

Step-by-step explanation:

Given

x^2 - 5x - 7 = 0

Required

Solve for x using:

x = \frac{-b \± \sqrt{b^2 - 4ac}}{2a}

First, we need to identify a, b and c

The general form of a quadratic equation is:

ax^2 + bx + c = 0

So, by comparison with x^2 - 5x - 7 = 0

a = 1     b = -5      c = -7

Substitute these values of a, b and c in

x = \frac{-b \± \sqrt{b^2 - 4ac}}{2a}

x = \frac{-(-5) \± \sqrt{(-5)^2 - 4 * 1 * -7}}{2 * 1}

x = \frac{5 \± \sqrt{25 +28}}{2}

x = \frac{5 \± \sqrt{53}}{2}

Split the expression to two

x = \frac{5 + \sqrt{53}}{2}  or  x = \frac{5 - \sqrt{53}}{2}

To solve further in decimal form, we have

x = \frac{5 + 7.28}{2}  or  x = \frac{5 - 7.28}{2}

x = \frac{12.28}{2}  or  x = \frac{-2.28}{2}

x = 6.14 or x = -1.14

4 0
3 years ago
Show the work please
frosja888 [35]

Answer: x = 9/2

Step-by-step explanation: 24 = 4x + 6

7 0
3 years ago
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Amiraneli [1.4K]
Subtract from the 2 and 8
7 0
2 years ago
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