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MA_775_DIABLO [31]
3 years ago
5

HELP PLEASE!!

Mathematics
2 answers:
shutvik [7]3 years ago
8 0

Answer:

6.5 x 10^6 To answer this question, you need to divide the mass of the sun by the mass of mercury. So 2.13525 x 10^30 / 3.285 x 10^23 = ? To do the division, divide the mantissas in the normal fashion 2.13525 / 3.285 = 0.65 And subtract the exponents. 30 - 23 = 7 So you get 0.65 x 10^7 Unless the mantissa is zero, the mantissa must be greater than or equal to 0 and less than 10. So multiply the mantissa by 10 and then subtract 1 from the exponent, giving 6.5 x 10^6 So the sun is 6.5 x 10^6 times as massive as mercury.

:}

pogonyaev3 years ago
4 0

6.5 x 10^6 To answer this question, you need to divide the mass of the sun by the mass of mercury. So 2.13525 x 10^30 / 3.285 x 10^23 = ? To do the division, divide the mantissas in the normal fashion 2.13525 / 3.285 = 0.65 And subtract the exponents. 30 - 23 = 7 So you get 0.65 x 10^7 Unless the mantissa is zero, the mantissa must be greater than or equal to 0 and less than 10. So multiply the mantissa by 10 and then subtract 1 from the exponent, giving 6.5 x 10^6 So the sun is 6.5 x 10^6 times as massive as mercury.

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nikklg [1K]

Answer:

A.  :)

Step-by-step explanation:

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What is 6(-7+6i)(-4+2i)?
cricket20 [7]
6-2-1=185666iiiiy6663636
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Find the 12th term of an AP of the form 7, 12, 17, 22
Nostrana [21]

Answer:

27

Step-by-step explanation:

The rule will be

Ni=(i-1)*5+2

  • i=1 → N=(1–1)*5+2=0*5+2=0+2=2
  • i=2 → N=(2–1)*5+2=1*5+2=5+2=7
  • i=3 → N=(3–1)*5+2=2*5+2=10+2=12
  • i=4 → N=(4–1)*5+2=3*5+2=15+2=17
  • i=5 → N=(5–1)*5+2=4*5+2=20+2=22
  • i=6 → N=(6–1)*5+2=5*5+2=25+2=27

________________

Learn more about arithmetic sequences:

  • brainly.com/question/6561461
  • brainly.com/question/503167

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6 0
2 years ago
How many pounds are in<br> 8 kilograms? 1 kg = 2.2 lbs<br><br> 8 kg = [?] lbs
ElenaW [278]

Answer:

17.6 lbs

Step-by-step explanation:

1kg=2.2lbs

Multiply each side by 8

8kg=17.6 lbs

5 0
3 years ago
Read 2 more answers
A spring with a spring constant k of 100 pounds per foot is loaded with 1-pound weight and brought to equilibrium. It is then st
shutvik [7]

Answer:

Equation of movement y(t)

y(t)=sin(10t-\pi/2)

Amplitude: 1 inch

Period: 0.628 seconds

Step-by-step explanation:

If there is no friction, the amplitude will be the length it was streched from the equilibrium. In this case, this value is 1 inch

A=1\,inch

The period depends on the mass and the spring constant.

The formula for the period is:

T=\frac{1}{f} =\frac{2/pi}{\omega} =2\pi\sqrt{\frac{m}{k}}=2\pi\sqrt{\frac{1}{100}}=2\pi*0.1=0.628\, s

The model y(t) for the movement of the mass-spring system is

y(t)=A\cdot sin(\omega t +\phi)\\\\A=1\\\\\omega=\sqrt{k/m} =\sqrt{100/1}=10\\\\y(0)=Asin(\phi)=-A\\\\ \phi=arcsin(-1)=-1.571=-\pi/2\\\\\\y(t)=sin(10t-\pi/2)

8 0
3 years ago
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