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stepan [7]
4 years ago
12

What are the solutions to the inequality (x-3)(x+5) ≤ 0

Mathematics
2 answers:
AleksAgata [21]4 years ago
8 0

Answer:

d

Step-by-step explanation:

DaniilM [7]4 years ago
7 0
1. Solve for x
x= 3 or x=-5

2. From the values of x above, we have these 3 intervals to test
x<=-5
-5<=x<=3
x<=3

3. Pick a test point for each interval
For the interval x<=-5:
Lets pick x=-6. Then, (-6-3)(-6+5)<=0. After simplifying, we get 9<=0, which is false. So we drop this interval.

For the interval -5<=x<=3:
Lets pick x=0. Then (0-3)(0+5)<=0. After simplifying, we get -15<=0, which is true. So we keep this interval.

For the interval x>=3:
Lets pick x=4. Then, (4-3)/4+5)<=0. After simplifying, we get 9<=0, which is false. So we drop this interval.

4. Therefore, 
-5<=x<=3.
The answer is therefore number 3 :D
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Simplify.<br><br><br><br> If d = –3, evaluate –d.<br><br><br><br> –3<br><br> 1<br><br> 0<br><br> 3
AnnZ [28]
-d would equal 3. just flip its around right?
7 0
3 years ago
In a survey of 400 seniors, x percent said that they plan on majoring in physics. One university has used this data to estimate
azamat

Answer:

2 percent

Step-by-step explanation:

We can use two separate fractions, one representing the amount of physics majors expected and the amount of seniors expected in physics majors by the university.

\frac{400x}{66} = \frac{400}{3600}

Now cross multiply.

\frac{66*400}{400x * 3600}

x will be removed.

\frac{26400}{1320000}

Simplifying this fraction will get you \frac{1}{50}, which in percentage form, will be 2 percent.

8 0
2 years ago
Identify the following polygons with the most specific name. Please she jpg for shapes and choices.
ExtremeBDS [4]

Answer:

isosceles trapezoid

Step-by-step explanation:

honestly not 100% sure but it seems the most specific

5 0
3 years ago
Find the area of the shape below.
m_a_m_a [10]

Answer:

 A_{shape}=A_{triangle}+A_{square}\\\\A_{shape}=(\frac{bh}{2}+s^2)\ units^2

Step-by-step explanation:

I assume that it is a composed figure formed by a triangle and a square.Since you did not  give the dimensions of the triangle and the dimensions of the square, I will giveyou  a general explanation about how to solve this exercise.

The area of the shape will be the sum of the the area of the square and the area of the triangle.

Then, you need to remember that the area of a triangle can be calculated with the following formula:

A_{triangle}=\frac{bh}{2}

Where "b" is the base and "h" is the height.

And the area of a square can be found with this formula:

A_{square}=s^2

Where "s" is the length of any side of the square.

Therefore, the area of the shape will be

 A_{shape}=A_{triangle}+A_{square}\\\\A_{shape}=(\frac{bh}{2}+s^2)\ units^2

3 0
3 years ago
The area of a rectangle with base b and height h is bh. A rectangular sports goal is 10ft wide and 8 ft high. Find the area of t
bogdanovich [222]

A = bh

A = 10(5)

A = 50 ft2

8 0
3 years ago
Read 2 more answers
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