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3 years ago

Jesses mom.gave him 45$ to buy snacks at school he spends 15 every two weeks

Mathematics

1 answer:

Black_prince [1.1K]3 years ago

4 0

Answer:

ok?

whats the queston?

if its devide it is 3

Step-by-step explanation:

45=15x3

15/45=3

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3 years ago

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olga55 [171]

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3 years ago

A sample of students is taken from the school's A honor roll. The school estimates that there are actually 360 students on the A

Sergio [31]

Answer:

Number of 8th Graders = 360 - X

Step-by-step explanation:

As you can see this question is not complete and lacks the essential data. But we will try to create a mathematical expression to calculate the number of students on the A honor roll which are from 8th grade.

As we know:

Total number of students on the A honor roll = 360

We are asked to calculate, number of students from 8th grade on the A honor roll.

So, let's assume that "X" represents the all the students who are on the A honor roll except 8th grade.

Mathematical Expression:

Number of 8th Graders = Total number of students on the A honor roll - X

Number of 8th Graders = 360 - X

So, if you know the value of X, you can easily calculate the number of students which are from 8th grade on the A honor roll.

3 0

3 years ago

A surveyor leaves her base camp and drives 42km on a bearing of 032degree she then drives 28km on a bearing of 154degree,how far

ValentinkaMS [17]

Answer:

The surveyor is 36.076 kilometers far from her camp and her bearing is 16.840° (standard form).

Step-by-step explanation:

The final position of the surveyor is represented by the following vectorial sum:

$\vec r = \vec r_{1} + \vec r_{2} + \vec r_{3}$ (1)

And this formula is expanded by definition of vectors in rectangular and polar form:

$(x,y) = r_{1}\cdot (\cos \theta_{1}, \sin \theta_{1}) + r_{2}\cdot (\cos \theta_{2}, \sin \theta_{2})$ (1b)

Where:

$x, y$ - Resulting coordinates of the final position of the surveyor with respect to origin, in kilometers.

$r_{1}, r_{2}$ - Length of each vector, in kilometers.

$\theta_{1}, \theta_{2}$ - Bearing of each vector in standard position, in sexagesimal degrees.

If we know that $r_{1} = 42\,km$ , $r_{2} = 28\,km$ , $\theta_{1} = 32^{\circ}$ and $\theta_{2} = 154^{\circ}$ , then the resulting coordinates of the final position of the surveyor is: