Please help me out with this please and thank you No links no stealing points
1 answer:
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Given:
The parent absolute function is
To find:
The new function if the parent function is translated up by 5 units and vertically stretched by a factor of 3.
Solution:
The translation is defined as
.... (1)
Where, k is stretch factor, a is horizontal shift and b is vertical shift.
If 0<k<1, then the graph compressed vertically by factor k and if k>1, then the graph stretch vertically by factor k.
If a>0, then the graph shifts a units left and if a<0, then the graph shifts a units right.
If b>0, then the graph shifts b units up and if b<0, then the graph shifts b units down.
Parent function is translated up by 5 units. So, b=5
It is vertically stretched by a factor of 3. So, k=3.
There is no horizontal shift. So, a=0.
Now, putting k=3, a=0 and b=5 in (1), we get
Therefore, the correct option is D.
Answer:
The correct option is 1.
Step-by-step explanation:
The difference of cubes is defined as
The given expression is
It can be written as
Using the property of exponent, the above expression can be written as
This is a difference of cubes.
Therefore the correct option is 1.
Answer:
> a<-rnorm(20,50,6)
> a
[1] 51.72213 53.09989 59.89221 32.44023 47.59386 33.59892 47.26718 55.61510 47.95505 48.19296 54.46905
[12] 45.78072 57.30045 57.91624 50.83297 52.61790 62.07713 53.75661 49.34651 53.01501
Then we can find the mean and the standard deviation with the following formulas:
> mean(a)
[1] 50.72451
> sqrt(var(a))
[1] 7.470221
Step-by-step explanation:
For this case first we need to create the sample of size 20 for the following distribution:
And we can use the following code: rnorm(20,50,6) and we got this output:
> a<-rnorm(20,50,6)
> a
[1] 51.72213 53.09989 59.89221 32.44023 47.59386 33.59892 47.26718 55.61510 47.95505 48.19296 54.46905
[12] 45.78072 57.30045 57.91624 50.83297 52.61790 62.07713 53.75661 49.34651 53.01501
Then we can find the mean and the standard deviation with the following formulas:
> mean(a)
[1] 50.72451
> sqrt(var(a))
[1] 7.470221