Let
L=event that a selected worker has low risk
H=event that a selected worker has high risk
We need to find
P(HL)+P(LH)
=5*20/(25*24)+20*5/(25*24)
=1/6+1/6
=1/3
((-4x^3)(y^4))^-3
--------------------------
(2xy^4)^-4
16x^4y^16
=------------------------
-64x^9y^12
-16y^4
=------------------------
64x^5
-y
=------------------------
4x^5
So the final answer is:
-y^4
-------
4x^5
(Btw if "^" is in front of a number, that means it is an exponent, so when your writing this on paper, just write it as a regular exponent without the "^". I had to do that since I'm on a computer.)
Hopefully this was helpful in some way.
If you have a rectangle with an area of 32 square feet, it means that the sides are
A=L x W, 32= 8*4, where
L=8, W=4
other options are
L=16, W=2 and the last one is
L=32, W=1
You need to find the least perimeter , and you know that the perimeter is P= 2(L+W)
Perimeter (1)= 2(8+4)=2*12=24
Perimeter(2)= 2(16+2)=2*18=36
Perimeter (3)=2(32+1)=2*33=66
The least perimeter is 24, with the sides L=8 and W=4
Given :
A function , x = 2cos t -3sin t .....equation 1.
A differential equation , x'' + x = 0 .....equation 2.
To Find :
Whether the given function is a solution to the given differential equation.
Solution :
First derivative of x :
Now , second derivative :
( Note : derivative of sin t is cos t and cos t is -sin t )
Putting value of x'' and x in equation 2 , we get :
=(-2cos t + 3sin t ) + ( 2cos t -3sin t )
= 0
So , x'' and x satisfy equation 2.
Therefore , x function is a solution of given differential equation .
Hence , this is the required solution .
A 270° counterclockwise rotation leads to this transformation:
(x,y) → (y, - x)
So, we have
original point new point
J (-6,2) → J' (2,6)
K (-4,6) → K' (6,4)
L (-3,3) → L' (3,3)
M (-5,-1) → M' (-1,5)
So, you have the points J', K', L', and M' that define the new parallelogram.
Answer: The coordinates of the endpoints of the side congruent to side KL are the coordinates of K' and L' which are (6,4) and (3,3).
