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stealth61 [152]
3 years ago
15

Super Salad Dressing is made with 8\text{ mL}8 mL8, start text, space, m, L, end text of oil for every 3\text{ mL}3 mL3, start t

ext, space, m, L, end text of vinegar.
Which of the following mixtures will taste the same as Super Salad Dressing?
Choose 3 answers:
Choose 3 answers:

(Choice A)
A
80\text{ mL}80 mL80, start text, space, m, L, end text of oil with 30\text { mL}30 mL30, start text, space, m, L, end text of vinegar

(Choice B)
B
3\text{ mL}3 mL3, start text, space, m, L, end text of oil with 8\text { mL}8 mL8, start text, space, m, L, end text of vinegar

(Choice C)
C
56\text{ mL}56 mL56, start text, space, m, L, end text of oil with 21\text { mL}21 mL21, start text, space, m, L, end text of vinegar

(Choice D)
D
40\text{ mL}40 mL40, start text, space, m, L, end text of oil with 25\text { mL}25 mL25, start text, space, m, L, end text of vinegar

(Choice E)
E
48\text{ mL}48 mL48, start text, space, m, L, end text of oil with 18\text { mL}18 mL18, start text, space, m, L, end text of vinegar
Mathematics
1 answer:
DanielleElmas [232]3 years ago
8 0

Answer: A, C, and E! I just took this on Khan Academy! Please mark me brainliest because it it correct!

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Answer:

a_{n} = 4n + 3

Step-by-step explanation:

Note there is a common difference d between consecutive terms, that is

d = 11 - 7 = 15 - 11 = 19 - 15 = 4

This indicates the sequence is arithmetic with n th term

a_{n} = a₁ + (n - 1)d

where a₁ is the first term and d the common difference

Here a₁ = 7 and d = 4, thus

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Answer:

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oksano4ka [1.4K]

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3 years ago
A restaurant chain is measuring the levels of arsenic in chicken from its suppliers. The question is whether there is evidence t
Natalija [7]

Answer:

The p-value of the test is 0.1515.

Step-by-step explanation:

The hypothesis for the test can be defined as follows:

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<em>Hₐ</em>: The mean level of arsenic is greater than 80 ppb, i.e. <em>μ</em> > 80.

As the population standard deviation is not known we will use a t-test for single mean.

It is provided that the sample mean was, \bar X=91.

The adjusted sample provided is:

S = {57, 64, 70, 82, 84, 123}

Compute the sample standard deviation as follows:

\bar x=\farc{57+64+70+82+84+123}{6}=80\\\\s=\sqrt{\frac{1}{6-1}\times [(57-80)^{2}+(64-80)^{2}+(70-80)^{2}+...+(123-80)^{2}]}=23.47

Compute the test statistic value as follows:

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Thus, the test statistic value is 1.148.

Compute the p-value of the test as follows:

 p-\text{value}=P(t_{n-1}

                =P(t_{6-1}

*Use a t-table.

Thus, the p-value of the test is 0.1515.

Decision rule:

If the <em>p</em>-value of the test is less than the significance level then the null hypothesis will be rejected and vice-versa.

p-value = 0.1515 > α = 0.05

The null hypothesis will not be rejected at 5% level of significance.

Thus, concluding that the mean level of arsenic in chicken from the suppliers is 80 ppb.

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ehidna [41]

Answer:

25000

Step-by-step explanation:

(10000/40)*100 = 25000

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