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Alja [10]
3 years ago
12

What is the result when you run the following program?

Computers and Technology
1 answer:
dexar [7]3 years ago
5 0

Answer:

The answer to this question is given below in the explanation section.

Explanation:

If you run the following program,

print(2 + 7)

print("3+1")

then, you can get the following result respectively against each print statement.

9

3+1

because when you print 2+7 without quotation, it will add the integer digit and print the result of adding 2 and 7.

And, when you run ("3+1") in the double quotation, the program will treat it as a string because of the enclosed double quotation (" ");

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In a java class, variables can be present both inside and outside of methods. question 9 options:
Tems11 [23]
The correct answer is: True

Explanation:

Consider the following program:
<span>class Main {
int a = 10;
public static void main(String[] args) {
add();
}

private static void add() {
int b = a+20;
System.out.println(b);
}<span>
}


The output of the above program is 30. As you can see the variable a is declared outside the method, whereas variable b is declared inside the method.</span></span>
3 0
3 years ago
An alternative to hexadecimal notation for representing bit patterns is dotted decimal notation in which each byte
zysi [14]

An alternative to hexadecimal notation for representing bit patterns is dotted decimal notation in which each byte in the pattern is represented by its base ten equivalent. In turn, these byte representations are separated by periods. For example, 12.5 represents the pattern 0000110000000101 (the byte00001100 is represented by 12, and 00000101 is represented by 5), and the pattern 100010000001000000000111 is represented by 136.16.7. Represent each of the following bit patterns in dotted decimal notation,

a. 0000111100001111 b. 001100110000000010000000c. 0000101010100000

4 0
3 years ago
Using MARS/MIPS
slega [8]

Answer:

Explanation:

MIPS program which increments from 0 to 15 and display results in Decimal on the console

In this program the user defined procedures print_int and print_eot were used to print the integer values and new line characters(\n) respectively.the mechanisam of the loop is explaine in the comment section of the program.

     addi $s0, $0, 0

     addi $s1, $0, 15

print_int:

              li $v0, 1                # system call to print integer

              syscall                

              jr $ra                     # return

print_eol:                      # prints "\n"

            li $v0, 4            

              la $a0, linebrk      

              syscall              

              jr $ra                  # return

main: . . .          

              li $a0, 0                # print 0

              jal print_int         # print value in $a0

loop:   move $a0, $s0           # print loop count

       jal print_int        

       jal print_eol           # print "\n" character

       addi $s0, $s0, 1        # increment loop count by 1

       ble $s1, $s0, loop      # exit if $s1<$s0

beq $s0, $0, end

end:

MIPS progam to increment from 0 to 15 and display results in Hexadecimal on the console

this program is slightly differed from the previous program in this program the system call issued in print_int is implemented with a system call that prints numbers in hex.

addi $s0, $0, 15

     addi $s1, $0, 0

print_int:

   li      $v0,34                  # syscall number for "print hex"

   syscall                         # issue the syscall

              jr $ra                     # return

print_eol:                      # prints "\n"

            li $v0, 4            

              la $a0, linebrk      

              syscall              

              jr $ra                  # return

main: . . .          

              li $a0, 0                # print 0

              jal print_int         # print value in $a0

loop:   move $a0, $s0           # print loop count

       jal print_int        

       jal print_eol           # print "\n" character

       addi $s0, $s0, 1        # increment loop count by 1

       ble $s1, $s0, loop      # exit if $s0>$s1

beq $s0, $0, end

end:

5 0
3 years ago
Find the maximum value and minimum value in below mention code. Assign the maximum value to maxMiles, and the minimum value to m
Kobotan [32]

Answer:

Code works perfectly

Explanation:

There is nothing wrong with your program as it runs perfectly and displays the expected results.

You may need to compile with another compiler if you're not getting the required results.

I've added the source code as an attachment (unedited)

Download java
3 0
3 years ago
A tooltip is a _____________ that allows the programmer to create a small popup message that displays when the user places the m
Shalnov [3]
I believe a message
7 0
3 years ago
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