the given is a square pyramid. The side length of the base of the pyramid is 28 millimeters. The volume of the pyramid is 1296 c
ubic mm. What is the height of the pyramid
1 answer:
Hi! the answer is 2+[8x1296] because you break the 28 and the 1296 stays the same
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I belive it would be 12x + 12y
x² - 5x - 6
= x² + x - 6x - 6
= x(x + 1) - 6(x + 1)
= (x - 6) (x + 1)
x² + 3x - 40
= x² + 8x - 5x - 40
= x(x + 8) -5(x + 8)
= (x - 5) (x + 8)
x² + 3x - 4
= x² + 4x - x - 4
= x(x + 4) -1(x + 4)
= (x - 1) (x + 4)
True, each number is getting doubled, both sides are proportionally staying the same.
Answer:
y=1.2x-3
Step-by-step explanation:
I had this as an rsm problem a few weeks ago and forgot how to solve it lol hope this helps
