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makkiz [27]
3 years ago
7

Please help me is for my daughter ​

Mathematics
1 answer:
lana66690 [7]3 years ago
6 0

Step-by-step explanation:

To find 5/6 of the area, multiply the area that was found in part A , as the question states by 5/6.

⅚ × Area found in part A.

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Please someone know this ?
sladkih [1.3K]

Answer:

sas fact congruency

Step-by-step explanation:

angle and same side are given

both triangle have same side

3 0
3 years ago
If you have 1-cup servings of juice to 30 people, how many whole gallons of juice will you need?
Ratling [72]

Answer:

2 gallons

Step-by-step explanation:

there are 16 cups in a gallon. if you have 30 cups for people, do 30/16=1.875 which you cant have 0.875 gallons of juice, so you need to round it to two gallons.

3 0
4 years ago
Read 2 more answers
40 POINTS WILL MARK BRAINLIEST!!!
Leviafan [203]

Answer:

When Jamal Crawford comes to the free throw line, in the 2012-2013 NBA season, he would make 871 free throws out of 1000.  Therefore, his percentage of making a free throw would by %87.1

6 0
3 years ago
Which graph models the solution set of 50x + 150y>1500?
hodyreva [135]

Answer:

see attached diagram

Step-by-step explanation:

First, draw the dashed line 50x+150y=1500 (dashed because the inequality is without notion "or equal to"). You can do it finding x and y intercepts.

When x=0, then 150y=1500, y=10.

When y=0, then 50x=1500, x=30.

Connect points (0,10) and (30,0) to get needed dashed line.

Then determine which region (semiplane) you have to choose. Note that origin's coordinates  (0,0)  do not satisfy the inequality 50x + 150y>1500, because

50\cdot 0+150\cdot 0=0

This means that origin lies outside the needed region, so you have to choose the semiplane that do not contain origin (see attached diagram).


4 0
3 years ago
Read 2 more answers
Can someone please help me​
astra-53 [7]

Answer:

square 20 has 44 green squares

square 21 has 45 green squares

Step-by-step explanation:

To solve the problem, we need to observe the cases, and determine/define a rule for each case (odd number of sides, or even number of sides).

For square one, we note that the centre square is shared by two diagonals, so we saved one square from the two diagonals.

The side length is 3 for square 1, 4 for square 2, and so on.

Let

n= square number (1, 2,3...)

L = side length (3,4,5...)

G1(n) = function that gives the number of green squares for square n, n=odd

G2(n) = function that gives the number of green squares for square n, n=even

side length, L=n+2   ................(1)

G1(n) = twice the side length less one, as discussed above

G1(n) = 2L-1       now substitute L=n+2

G1(n) = 2(n+2) -1    simplify

G1(n) = 2n + 3

Check:

for n=1, square 1 has 2*1+3 = 5 green squares ... checks

for n=3, square 3 has 2*3+3 = 9... checks

for n=5, square 5 has 2*5+3 = 13 ....checks

For even squares, it is even easier, because

G2(n) = 2L = 2(n+2)

check:

for n=2, square 2 has 2(2+2) = 8 green squares........checks

for n=4, square 4 has 2(4+2) = 12 green squares........checks.

Fincally, we apply our formula to n=20 and n=21

square 20 : G2(20) = 2(n+2) = 2(20+2) = 44 green quars

square 21 : G1(21) = 2n+3 = 2(21)+3 = 45 green squares

5 0
3 years ago
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