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3 years ago

In a network, multiple critical paths can occur. true or false

2 answers:

4 0

This can be the result of multiple dependencies between tasks, or separate sequences that run for the same duration. TRUE

vitfil [10]3 years ago

3 0

Answer:

I think it's True but I'm not sure

Explanation:

I hope it's help u

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Wireshark capture files, like the DemoCapturepcap file found in this lab, have a __________ extension, which stands for packet c

VashaNatasha [74]

Answer:

Option (d) is correct

Explanation:

Previously saved capture files can be read using Wireshark. For this, select the File then open the menu. Then Wireshark will pop up the “File Open” dialog box.

Wireshark capture files, like the DemoCapturepcap file found in this lab, have a .pcapng extension, which stands for packet capture, next generation.

5 0

2 years ago

Identify the operation which is NOT one of the parts of the fivebasic set operations in relational algebra?

wariber [46]

Answer:

Join

Explanation:

Five basic set operators in relational algebra are as follows:

Selection - tuple selection
Projection - extract columns
Cartesian product - cross product of relations
Set union - union of two relations
Set difference - minus operation on two relations

As we can see, Join is not part of the basic set operations but it is implemented using the Cartesian Product operator.

5 0

3 years ago

Given the following code: public class Test { public static void main(String[] args) { Map map = new HashMap(); map.put("123", "

Phoenix [80]

Answer:

There are no statements in the question, so I explained the whole code.

Explanation:

A map consists of key - value pairs. The put method allows you to insert values in the map. The first parameter in the put method is the key, and the second one is the value. Also, the keys must be unique.

For example, map.put("123", "John Smith"); -> key = 123, value = John Smith

Even though the key 123 is set to John Smith at the beginning, it will have the updated value Steve Yao at the end. That is because the keys are unique.

Note that the key 222 also has Steve Yao for the value, that is totally acceptable.

5 0

2 years ago

Assume that an array of Integers named a that contains exactly five elements has been declared and initialized. In addition, an

just olya [345]

Complete Question:

Assume that an array of Integers named a that contains exactly five elements has been declared and initialized. In addition, an int variable j has also been declared and initialized to a value somewhere between 0 and 3.

Write a single statement that assigns a new value to the element of the array indexed by j. This new value should be equal to twice the value stored in the next element of the array (i.e. the element after the element indexed by j ). Do not modify any other elements of the array!

Answer:

a[j] = 2 * a[j+1];

Explanation:

Since the array is named a and its indexes are referenced by the variable j

it means the elements of the array will be a[j] for (j=0; j=1;j=2).

The first element in the array (j=0) will be a[0], second element will be a[1] and so on.

The statement a[j] = 2 * a[j+1]; assigns a new value to the element of the array indexed by j, the value is equal to twice the value stored in the next element of the array (j+1).

4 0

3 years ago

Now, extend your test program by adding a second function named split that will identify all the individual values in a comma se

otez555 [7]

Answer:

The code to copy is :

#include <iostream>

#include <string>

using namespace std;

string nextString(string str, int start_index);

int split(string str, string a[], int max_size);

int main()

{

const int VALUES = 20;

string somestring;

string varray[VALUES];

//Prompt the user to enter a comma separated string

cout << "Enter a comma seperated string: ";

//read the string

getline(cin, somestring);

//call split() method on the given string and

//store the count of individual strings in cnt

int cnt = split(somestring, varray, VALUES);

//Print the individual strings

for (int i = 0; i<cnt; i++)

cout << varray[i] << endl;

return 0;

}

//returns a sub string that starts at strat_index

//in the given string and ends before a comma

string nextString(string str, int start_index)

{

int i;

//find a comma or end of the string, after strat_index

for (i = start_index;i < str.length();i++)

{

//if comma is found, exit the loop

if (str.at(i) == ',')

break;

}

//extract the sub string

string out= str.substr(start_index, i-start_index);

return out;

}

//splits the comma separted string as individual strings

//and returns the number of individual strings

int split(string str, string a[], int max_size)

{

int i, j;

int start_index = 0;

//search for commas in the given string

for (i = 0,j=0;i < str.length();i++)

{

//if comma is identified or end of the string is identified

//, then get a strig that starts at start_index using next string

if (str.at(i) == ',' ||i==str.length()-1)

{

//save each string into an array of strings

a[j] = nextString(str, start_index);

//update the next string starting postion(starts after comma)

start_index = i + 1;

j++;

}

return j;

Explanation:

Please see attachments

7 0

3 years ago