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NISA [10]
3 years ago
9

Password is 1234 ....

Physics
2 answers:
andrew11 [14]3 years ago
8 0

Answer:

Thanks for the points I appreciate it.

Explanation:

Have a great day :)

irina1246 [14]3 years ago
3 0

Answer:

okay

Explanation:

have a nice day :)  stay hydrated.

‧₊˚ ꒰ mei ꒱ ‧₊˚

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A train with mass 3.3 x 107 kg starts from rest and accelerates to a speed of 42
Natasha2012 [34]

Answer:

kinetic energy of the train = 2,910.6 x 10⁷ joule

Explanation:

Given:

Mass of train = 3.3 x 10⁷ kg

Speed of train = 42 m/s

Find:

kinetic energy of the train

Computation:

kinetic energy = (1/2)(m)(v²)

kinetic energy of the train = (1/2)(3.3 x 10⁷)(42²)

kinetic energy of the train = (1/2)(3.3 x 10⁷)(1,764)

kinetic energy of the train = (3.3 x 10⁷)(882)

kinetic energy of the train = 2,910.6 x 10⁷ joule

4 0
3 years ago
Read 2 more answers
A wave is represented by the equation y = 0.20 sin [ 0.4π (x – 60t)], where x and y are in cm and t is in s. The velocity of the
Leya [2.2K]

Answer:

v = 60 m/s

Explanation:

It is given that,

A wave is represented by the equation :

y=0.2\sin [0.4\pi (x-60)t]

We need to find the velocity of the wave

The general equation of a wave is given by :

y=A\sin (kx-\omega t) ....(1)

Equation (1) can be written as :

y=0.2\sin (0.4\pi x-24\pi t) ...(2)

If we compare equation (1) and (2) we get :

k=0.4\pi

\omega=24\pi

The velocity of a wave is given by :

v=\dfrac{\omega}{k}\\\\v=\dfrac{24\pi}{0.4\pi}\\\\v=60\ m/s

So, the velocity of the wave is 60 m/s.

6 0
3 years ago
HELPP ITS DUE IN 5 MINUTES FREE BODY DIAGRAMS
Rashid [163]

Answer:

C i think sorry if inmccorect

Explanation:

5 0
3 years ago
Read 2 more answers
A 5.0kg toolbox is raised from the ground by a rope. If the upward acceleration of the bucket is 2.5 m/s^2, find the force exert
swat32

Answer:

62 N

Explanation:

Sum of the forces on the toolbox:

∑F = ma

T − mg = ma

T = mg + ma

T = m (g + a)

T = (5.0 kg) (9.8 m/s² + 2.5 m/s²)

T = 61.5 N

Rounded to two significant figures, the force exerted by the rope is 62 N.

8 0
4 years ago
he primary coil of a transformer is connected to 240 V ac supply. The induced secondary voltage is 60 V. If the ac current in th
vovikov84 [41]

Answer:

Secondary current is  8A

Explanation:

Data :

Primary supply = Vp = 240 V

Secondary supply = Vs = 60V

Primary current = Ip = 2A

Secondary current = Is = ?

Formula  :     Vp × Ip = Vs × Is

So for secondary current formula becomes

          Is = (Vp/Vs)×Ip =  (240/60) × 2

     Is = 4 × 2 = 8A

6 0
2 years ago
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