Answer:
v = 27.456 m/s
Explanation:
The support pressure needed of the water in the straw can be calculated by the formula
Given that,
P = r*g*h
= 1000*9.8*0.05 Pa.= 490 Pa
This pressure is compensated by 0.5*r*v^2 of the air,
Hence,
0.5*1.3*v^2 = 490
velocity of air blown into the straw =
v = 27.456 m/s
Answer:
It is<em> impossible</em> to construct a machine which produces the <em>work output greater than the work input.</em>
Let us consider the II law of thermodynamics.
According to Kelvin Plank's statement any engine/machine does not give hundred percent efficiency. And violating the PMM-II(Perpetual motion of machine II kind), Always some amount of energy transferred to the sink or surroundings.
Therefore
W(ouput) = Q₁-Q₂
There are many reasons to lower the work output, just for an example friction between the mating parts reduces the work output.
Answer:
P=9.58 W
Explanation:
According to Newton's second law, and assuming friction force as zero:
The acceleration is given by:
So the force exerted by the motor is:
The work done by the motor is given by:
And finally, the power is given by:
Answer:
This can be the FBD of the bag.
(my bag looks more like a box tho ^^")
Answer:
There is no change, unless your mass is somehow at the quantum level, at which the concept of half-life breaks down.
Half life is a property of the specific radioactive isotope...NOT of the initial sample's mass.
