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USPshnik [31]
3 years ago
8

Tell me the answer and help me explain please

Mathematics
2 answers:
DENIUS [597]3 years ago
6 0

Answer:

The answer is 9/10

Step-by-step explanation:

8/10 is the same thing as ⅘, ⅘ is just simplified

⅖ is less than ⅘ so it would come before c

6/5 is more than 1 so it wouldn’t be on that number line.

german3 years ago
3 0

Answer:

OK.

My answer is based on 2 things.

1. That the furthest point on the left is 0( That other little distance is ignored)

2. That the point C is equidistant from 4/5 and 1.

If so..

Then

4/5 + x + x =1

4/5 +2x = 1

2x= 1-4/5

x=1/10

Now

From 4/5 to C is x...

Then Position C would be

4/5 + 1/10

c= 9/10

Or by simply making guesses...

All Other options are greater than 1... So It can't be those cos C is less than 1

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4. You want to know if there's an association between college students' spring break destinations and what year they're in. You
Pachacha [2.7K]

Answer:

\chi^2 =27.356

p_v = P(\chi^2_{9} >27.356)=0.00122

And we can find the p value using the following excel code:

"=1-CHISQ.DIST(27.356,9,TRUE)"

Since the p value is lower than the significance level assumed 0.05 we can reject the null hypothesis at 5% of significance, and we can conclude that we have association between the two variables analyzed.

Step-by-step explanation:

A chi-square goodness of fit test "determines if a sample data matches a population".

A chi-square test for independence "compares two variables in a contingency table to see if they are related. In a more general sense, it tests to see whether distributions of categorical variables differ from each another".

Assume the following dataset:

                           Amusement Parks     Mexico    Home    Other    Total

Freshman                     23                         21            43          21         108

Sophomore                  34                         23            14          26        97

Junior                           25                         30            23         26        104

Senior                           27                         33             17         19         96

Total                            109                        107            97         92        405

We need to conduct a chi square test in order to check the following hypothesis:

H0: There is independence between the two random variables

H1: There is dependence between the two variables

The level os significance assumed for this case is \alpha=0.05

The statistic to check the hypothesis is given by:

\chi^2 =\sum_{i=1}^n \frac{(O_i -E_i)^2}{E_i}

The table given represent the observed values, we just need to calculate the expected values with the following formula E_i = \frac{total col * total row}{grand total}

And the calculations are given by:

E_{1} =\frac{109*108}{405}=29.07

E_{2} =\frac{107*108}{405}=28.53

E_{3} =\frac{97*108}{405}=25.87

E_{4} =\frac{92*108}{405}=24.53

E_{5} =\frac{109*97}{405}=26.11

E_{6} =\frac{107*97}{405}=25.63

E_{7} =\frac{97*97}{405}=23.23

E_{8} =\frac{92*97}{405}=22.03

E_{9} =\frac{109*104}{405}=27.99

E_{10} =\frac{107*104}{405}=27.48

E_{11} =\frac{97*104}{405}=24.91

E_{12} =\frac{92*104}{405}=23.62

E_{13} =\frac{109*96}{405}=25.84

E_{14} =\frac{107*96}{405}=25.36

E_{15} =\frac{97*96}{405}=22.99

E_{16} =\frac{92*96}{405}=21.81

And the expected values are given by:

                        Amusement Parks     Mexico    Home    Other    Total

Freshman                   29.07                28.53     25.87     24.53      108

Sophomore                26.11                  25.63     23.23     22.03      97

Junior                         27.99                 27.48     24.91      23.62     104

Senior                        25.84                 25.36     22.99      21.81       96

Total                            109                      107         97           92         405

And now we can calculate the statistic:

\chi^2 =27.356

Now we can calculate the degrees of freedom for the statistic given by:

df=(rows-1)(cols-1)=(4-1)(4-1)=9

And we can calculate the p value given by:

p_v = P(\chi^2_{9} >27.356)=0.00122

And we can find the p value using the following excel code:

"=1-CHISQ.DIST(27.356,9,TRUE)"

Since the p value is lower than the significance level assumed 0.05 we can reject the null hypothesis at 5% of significance, and we can conclude that we have association between the two variables analyzed.

7 0
3 years ago
Friday night a pizza parlor old five large pizza and ome medium pizza the Pizza parlor made a total of
DanielleElmas [232]

Friday night, a pizza parlor sold 5 large pizzas and some medium pizzas. The pizza parlor made a total of $291. How many medium pizzas were sold? Medium pizzas cost $9 and large pizzas cost $15

The large pizza costs $15 and earns $75, and the medium pizzas cost $9 and it earns $216. The large pizzas were sold 5, meanwhile, the medium pizzas were sold 24.

<h3>Why the pizza parlor sold 24 medium pizzas?</h3>

The pizza parlor made $291 from the large and medium pizzas.

The pizza parlor sold 5 large pizzas with cost $15.

5 × $15 = $75

$291 - $75 = $216

The pizza parlor sold … medium pizzas with cost $9.

$216 ÷ $9 = 24

The pizza parlor sold 24 medium pizzas.

Learn more about multiplication:

brainly.com/question/11574429

#SPJ4

8 0
2 years ago
Simplify the expression<br> 8s - 11s + 6
raketka [301]
8 s -11 s + 6= - 3 s + 6=
= 3( - s +2)
6 0
3 years ago
Read 2 more answers
Help please!!! can you show me how to do this??
IrinaK [193]
\frac{3x - 2}{x^{2} - 2x - 3} - \frac{1}{x - 3} = \frac{3x  -2}{(x + 1)(x - 3)} - \frac{1}{x - 3} = \frac{3x - 2}{(x + 1)(x - 3)} - \frac{1(x + 1)}{(x + 1)(x - 3)} = \frac{3x - 2}{(x + 1)(x - 3)} - \frac{x + 1}{(x + 1)(x - 3)} = \frac{2x - 3}{(x + 1)(x - 3)}
5 0
3 years ago
5^4/5^7 simplified is
Nuetrik [128]

\textbf{Given that,}\\\\~~~\dfrac{5^4}{5^7}\\\\\\=5^{4-7}~~~~~~~~~~~~~~~~~~~~~~~~;\textbf{Apply exponent rule:}~\dfrac{a^m}{a^n} = a^{m-n}\\\\\\=5^{-3}\\\\\\=\dfrac 1{5^3}~~~~~~~~~~~~~~~~~~~~~~~~~~;\textbf{Apply exponent rule:}~ a^{-n} = \dfrac 1 {a^n},~~~a \neq 0 \\\\\\=\dfrac 1{125}\\\\\\=0.008

5 0
2 years ago
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