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2 years ago

Tell me the answer and help me explain please

Mathematics

2 answers:

DENIUS [597]2 years ago

6 0

Answer:

The answer is 9/10

Step-by-step explanation:

8/10 is the same thing as ⅘, ⅘ is just simplified

⅖ is less than ⅘ so it would come before c

6/5 is more than 1 so it wouldn’t be on that number line.

german2 years ago

3 0

Answer:

OK.

My answer is based on 2 things.

1. That the furthest point on the left is 0( That other little distance is ignored)

2. That the point C is equidistant from 4/5 and 1.

If so..

Then

4/5 + x + x =1

4/5 +2x = 1

2x= 1-4/5

x=1/10

Now

From 4/5 to C is x...

Then Position C would be

4/5 + 1/10

c= 9/10

Or by simply making guesses...

All Other options are greater than 1... So It can't be those cos C is less than 1

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0.05 is 1/10 the value of what

Dafna1 [17]

Answer:

0.05

Explanation:

Let x = the number

.05 = .1x

5/100 = (1/10)x Multiply both sides by 10.

5/10 = x

1/2 = x

8 0

2 years ago

Given: m∠EYL=72°<br> Find: mEHL , mLVE

White raven [17]

Answer:

Part 1) The measure of arc EHL is $108\°$

Part 2) The measure of angle LVE is $54\°$

Step-by-step explanation:

step 1

Let

x-----> the measure of arc EHL

y----> the measure of arc EVL

we know that

The measurement of the outer angle is the semi-difference of the arcs it encompasses.

$m$

we have

$m$

substitute

$72\°=\frac{1}{2}(y-x)$

$144\°=(y-x)$

$y=144\°+x$ ------> equation A

Remember that

$x+y=360\°$ -----> equation B ( complete circle)

substitute equation A in equation B and solve for x

$x+(144\°+x)=360\°$

$2x=360\°-144\°$

$x=216\°/2=108\°$

Find the value of y

$y=144\°+x$

$y=144\°+108\°=252\°$

therefore

The measure of arc EHL is $108\°$

The measure of arc EVL is $252\°$

step 2

Find the measure of angle LVE

we know that

The inscribed angle measures half that of the arc comprising

Let

x-----> the measure of arc EHL

$m$

we have

$x=108\°$

substitute

$m$

3 0

2 years ago

Find the least common multiple of each pair of polynomials.<br> 5 y² - 80 and y + 4

kobusy [5.1K]

The least common multiple of each pair of the polynomial (5y² - 80) and

(y + 4) is equal to 5(y-4)(y+4).

As given in the question,

Given pair of the polynomial is (5y² - 80) and (y + 4)

Simplify the given polynomial using (a² -b²) = (a-b)(a +b)

(5y² - 80) = 5(y² -16)

⇒(5y² - 80) = 5(y² - 4²)

⇒(5y² - 80) = 5(y -4)(y + 4)

And (y + 4) = (1) (y+4)

Least common multiple = 5(y-4)(y+ 4)

Therefore, the least common multiple of the given pair of the polynomial is 5(y -4)(y+ 4).

Learn more about least common multiple here

brainly.com/question/11533141

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6 0

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The length of the major axis of the ellipse below is 12, and the length of the red line segment is 4

Alexxx [7]

Answer:

11/2

Step-by-step explanation:

The semi-major axis is 1/2 of the major axis, a, so a = 11/2.

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