A. They are both proportional because they have the same ratio.
b. The two graphs are the same because they have a constant rate of change (50), but they have different y-intercepts.
Answer:
up 2, right 3
Step-by-step explanation:
up 2, to the right 3.
Answer:
∠ ABC ≈ 137.9°
Step-by-step explanation:
Using the Cosine rule in Δ ABC
cos B = 
with a = 89, b = 144, c = 65
cos B =
=
=
, thus
B =
( -
) ≈ 137.9° ( to the nearest tenth )
Answer:
x + y = 36.....Equation 1
x = 7 + 2y...... Equation 2
Step-by-step explanation:
Let the number of:
Orange goldfish = x
Black gold fish = y
Anna has a total of 36 goldfish in her aquarium, some are orange and some are black.
x + y = 36.....Equation 1
The number of orange goldfish is 7 more than twice the number of black goldfish.
x = 7 + 2y...... Equation 2
We can rewrite this as:
x - 2y = 7..... Equation 2
The system of equations below that can be used to describe the number of black and orange goldfish in Anna's aquarium is :
x + y = 36.....Equation 1
x = 7 + 2y...... Equation 2
Answer;
The relevant probability is 0.136 so the value of 56 girls in 100 births is not a significantly high number of girls because the relevant probability is greater than 0.05
Step-by-step explanation:
The complete question is as follows;
For 100 births, P(exactly 56 girls = 0.0390 and P 56 or more girls = 0.136. Is 56 girls in 100 births a significantly high number of girls? Which probability is relevant to answering that question? Consider a number of girls to be significantly high if the appropriate probability is 0.05 or less V so 56 girls in 100 birthsa significantly high number of girls because the relevant probability is The relevant probability is 0.05
Solution is as follows;
Here. we want to know which of the probabilities is relevant to answering the question and also if 56 out of a total of 100 is sufficient enough to provide answer to the question.
Now, to answer this question, it would be best to reach a conclusion or let’s say draw a conclusion from the given information.
The relevant probability is 0.136 so the value of 56 girls in 100 births is not a significantly high number of girls because the relevant probability is greater than 0.05