PLEASE HELP THIS IS PYTHAGOREAN THEORM 3D

A worker has dug 5 holes for a fence post. It will take 20 minutes to dig each addional

anzhelika [568]

Answer:

it 100

Step-by-step explanation:

firs take the zero then time with the 5 it would give 10 n

then add the zero so 100

5 0

2 years ago

Suppose that g(x) = f(x) - 4. Which statement best compares the graph of

ArbitrLikvidat [17]

Answer:

The graph of g(x) is shifted 4 units down.

6 0

3 years ago

4ab (a -b) + b (2b -2a²) for a = 1 and b= -1 simplify it

aleksley [76]

Answer:

Step-by-step explanation:

4ab(a-b)+b(2b-2a^2)

=4*1*-1[1-(-1)]+(-1){2(-1)-2*1^2}

=-4(1+1)-1{-2-2}

=-4*2-1(-4)

=-8+4

=-4

3 0

3 years ago

Read 2 more answers

Given the probability distributions shown to the right, complete the following parts.

Elan Coil [88]

Answer:

a) Expected Value for distribution A, E(X) = 3.020

Expected Value for distribution B, E(X) = 0.980

b) Standard deviation of distribution A = 1.157

Standard deviation of distribution B = 1.157

c) In distribution A, the bigger values of x have a higher probability of occurring than the values of distribution B (whose smaller values of x have a higher chance of occurring, hence, the expected value for distribution A is more than that of distribution B.

But according to the corresponding distribution of values, the two distributions have the same exact spread, A in ascending order (with higher values with bigger probability) and B in descending order (lower values have higher probabilities). But the same spread regardless, hence, the standard deviation which shows how data values spread around the mean (centre point) of a distribution is the same for the two distributions.

Step-by-step explanation:

Expected values is given as

E(X) = Σ xᵢpᵢ

where xᵢ = each possible sample space

pᵢ = P(X=xᵢ) = probability of each sample space occurring.

Distributions A and B is given by

X P(X) X P(x)

0 0.04 0 0.47

1 0.09 1 0.25

2 0.15 2 0.15

3 0.25 3 0.09

4 0.47 4 0.04

For distribution A

E(X) = Σ xᵢpᵢ = (0×0.04) + (1×0.09) + (2×0.15) + (3×0.25) + (4×0.47) = 3.02

For distribution B

E(X) = Σ xᵢpᵢ = (0×0.47) + (1×0.25) + (2×0.15) + (3×0.09) + (4×0.04) = 0.98

b) Standard deviation = √(variance)

But Variance is given by

Variance = Var(X) = Σx²p − μ²

where μ = E(X)

For distribution A

Σx²p = (0²×0.04) + (1²×0.09) + (2²×0.15) + (3²×0.25) + (4²×0.47) = 10.46

Variance = Var(X) = 10.46 - 3.02² = 1.3396

Standard deviation = √(1.3396) = 1.157

For distribution B

Σx²p = (0²×0.47) + (1²×0.25) + (2²×0.15) + (3²×0.09) + (4²×0.04) = 2.30

Variance = Var(X) = 2.30 - 0.98² = 1.3396

Standard deviation = √(1.3396) = 1.157

c) In distribution A, the bigger values of x have a higher probability of occurring than the values of distribution B (whose smaller values of x have a higher chance of occurring, hence, the expected value for distribution A is more than that of distribution B.

But according to the corresponding distribution of values, the two distributions have the same exact spread, A in ascending order (with higher values with bigger probability) and B in descending order (lower values have higher probabilities). But the same spread regardless, hence, the standard deviation which shows how data values spread around the mean (centre point) of a distribution is the same for the two distributions.

7 0

3 years ago

If triangle CAT is similar to triangle DOG, which of the following statements is incorrect?

jeyben [28]

Answer:

1. triangle TCA ~ triangle GOD

4. If TC/GD=3/2, then m<T/m<G=3/2.

Step-by-step explanation:

The statements of the question are

1. triangle TCA ~ triangle GOD

2. AT: OG= AC:OD

3. If TC/GD=3/2, then AC/OD=3/2.

4. If TC/GD=3/2, then m<T/m<G=3/2.

5. If the scale factor of triangle CAT to triangle DOG is 3 to 2, then the scale factor of triangle DOG to triangle CAT is 2 to 3.

6. If AC is twice as long as AT, then OD is twice as long as OG

Verify each statement

1) triangle TCA ~ triangle GOD

we know that

If two triangles are similar, then the ratio of its corresponding sides is proportional and its corresponding angles are congruent

In this problem

triangle CAT ~ triangle DOG -----> is given

so

Reorder

Corresponding sides are named using pairs of letters in the same position on either side of the congruence statement

triangle TCA ~ triangle GDO

therefore

The statement is not correct

2). AT: OG= AC:OD

we know that

If two triangles are similar, then the ratio of its corresponding sides is proportional and its corresponding angles are congruent

In this problem

triangle CAT ~ triangle DOG -----> is given

so

Applying proportion

$\frac{AT}{OG}=\frac{AC}{OD}=\frac{TC}{GD}$

The statement is true

3). If TC/GD=3/2, then AC/OD=3/2.

we have that

$\frac{AT}{OG}=\frac{AC}{OD}=\frac{TC}{GD}$ ---> see part 2)

so

$\frac{TC}{GD}=\frac{AC}{OD}$

therefore

The statement is true

4). If TC/GD=3/2, then m<T/m<G=3/2

Remember that

In two similar triangles, corresponding angles are congruent

so

$m\angle T=m\angle G$

$m\angle T/m\angle G=1$

therefore

The statement is false

5). If the scale factor of triangle CAT to triangle DOG is 3 to 2, then the scale factor of triangle DOG to triangle CAT is 2 to 3

we know that

If the scale factor of triangle CAT to triangle DOG is a/b. then the scale factor of triangle DOG to triangle CAT is b/a

The scale factor will be the reciprocal

therefore

The statement is true

6). If AC is twice as long as AT, then OD is twice as long as OG

we know that

$\frac{AT}{OG}=\frac{AC}{OD}$

Reorder

$\frac{AT}{AC}=\frac{OG}{OD}$

If AC is twice as long as AT ----> AC=2AT

If OD is twice as long as OG ----> OD=2OG

substitute

$\frac{AT}{2AT}=\frac{OG}{2OG}$

simplify

$\frac{1}{2}=\frac{1}{2}$ ----> is true

therefore

The statement is true

5 0

3 years ago