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Answer: Option 'e' is correct.
Step-by-step explanation:
Since we have given that
Number of letters of the alphabet = 26
Number of letters in code :
One letter code, or two letter code, or three - letter code.
Since repetition of letters are allowed, then
if it is one letter code, the number of arrangement would be 26.
If it is two letter code, the number of arrangements would be
If it is three letter code, the number of arrangements would be
So, Number of different stocks to uniquely designate with these codes would be
Hence, Option 'e' is correct.
The problem based on condition are solved using the unknown variables. The number of tickets sold to the student are 120 and the number of tickets sold to the adults are 200.
Given information-
The price of the tickets for the basketball game for adults is $4.00.
The price of the tickets for the basketball game for students is $2.50.
<h3>Variables</h3>Variables are the unknown and the value of the variables depend on the other variables in the equation. The above problem can be solved defining the variables from the given condition.
Let the total tickets purchased by the students is<em> x</em> and the total tickets porches by the adults is <em>y.</em>
As the total tickets sold for the game is $320. Thus,
.......1
Now as the total money with ticket selling is $1100. Thus,
Keep the value of u from the equation 1 in the above equation. We get,
Thus the number of tickets sold to the student are 120.
Keep this value in equation 1,
Thus the number of tickets sold to the adults are 200.
Hence the number of tickets sold to the student are 120 and the number of tickets sold to the adults are 200.