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Luba_88 [7]
3 years ago
8

Which is the solution to the inequality? 1/4 + x < 5/6​

Mathematics
1 answer:
bogdanovich [222]3 years ago
4 0

Answer:

x<7/12

Step-by-step explanation:

1/4+x<5/6

24×1/4+24(x)<24×5/6

6+24x<20

24x<20-6

24x<14

24x/24<14/24

x<7/12

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Which best describes the relationship between the successive terms in the sequence shown?
Alex Ar [27]

Given series is 2.4,-4.8,9.6,-19.2

To find whether it has common difference or common ratio let us find few differences and few ratios of consecutive terms.

Common difference of first 2 terms = 2nd term - first term = -4.8-2.4 = -7.2

Common difference of 2nd and 3rd terms = 3rd term - 2nd term = 9.6-(-4.8) = 14.4

Since those common differences are not equal the given series does not have common difference at all.

To check if it has common ratio or not let us find few ratios of consecutive terms.

Common ratio of first 2 terms = \frac{2nd term}{first term} = \frac{-4.8}{2.4} = -2

Common ratio of 2nd and 3rd terms = \frac{3rd term}{2nd term} = \frac{9.6}{-4.8} = -2.0

So, the given series has common ratio as -2.0

7 0
3 years ago
Read 2 more answers
What is the median or 6,7,10,12,15,
natulia [17]

Answer:

10

Step-by-step explanation:

The median is the number in the middle of a group

4 0
4 years ago
A fair coin is tossed three time sin succession. the set of equally likely outcomes is {hhh,hht,hth,thh,htt,tht,tth,ttt}. find t
n200080 [17]
There are 8 possible outcomes so that means the probability will have a denominator of 8.

Now, there is only one of the eight outcomes that has zero tails.

Therefore the probability of getting zero tails after tossing a fair coin three times in succession is

​
\frac{1}{8}
6 0
3 years ago
The number of electrical outages in a city varies from day to day. Assume that the number of electrical outages ( x ) in the cit
forsale [732]

Answer:

Therefore, the mean and the standard deviation for the number of electrical outages (respectively) are 0.26 and 0.5765 respectively.

Step-by-step explanation:

Given the probability distribution table below:

\left|\begin{array}{c|cccc}x&0&1&2&3\\P(x)&0.8&0.15&0.04&0.01\end{array}\right|

(a)Mean

Expected Value, \mu =\sum x_iP(x_i)

=(0*0.8)+(1*0.15)+(2*0.04)+(3*0.01)

=0+0.15+0.08+0.03

Mean=0.26

(b)Standard Deviation

(x-\mu)^2\\(0-0.26)^2=0.0676\\(1-0.26)^2=0.5476\\(2-0.26)^2=3.0276\\(3-0.26)^2=7.5076

Standard Deviation =\sqrt{\sum (x-\mu)^2P(x)}

=\sqrt{0.0676*0.8+0.5476*0.15+3.0276*0.04+7.5076*0.01}\\=\sqrt{0.3324}\\=0.5765

Therefore, the mean and the standard deviation for the number of electrical outages (respectively) are 0.26 and 0.5765 respectively.

3 0
3 years ago
Find the midpoint of line CD given C(7, 5) and D(-3, -1)
Art [367]
Answer: C (2,-3)
Explanation: (x1+x2/2),(y1+y2/2)
3 0
3 years ago
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