We have that
<span>tan(theta)sin(theta)+cos(theta)=sec(theta)
</span><span>[sin(theta)/cos(theta)] sin(theta)+cos(theta)=sec(theta)
</span>[sin²<span>(theta)/cos(theta)]+cos(theta)=sec(theta)
</span><span>the next step in this proof
is </span>write cos(theta)=cos²<span>(theta)/cos(theta) to find a common denominator
so
</span>[sin²(theta)/cos(theta)]+[cos²(theta)/cos(theta)]=sec(theta)<span>
</span>{[sin²(theta)+cos²(theta)]/cos(theta)}=sec(theta)<span>
remember that
</span>sin²(theta)+cos²(theta)=1
{[sin²(theta)+cos²(theta)]/cos(theta)}------------> 1/cos(theta)
and
1/cos(theta)=sec(theta)-------------> is ok
the answer is the option <span>B.)
He should write cos(theta)=cos^2(theta)/cos(theta) to find a common denominator.</span>
Answer:
$750
Step-by-step explanation:
Answer:
- Define your variable and write your equation: 36 + b + (3b-28) = 180°.
- measure of the second angle: 43°.
- measure of the third angle: 101°
Step-by-step explanation:
a = 36
c = 3b - 28
a + b + c = 180°
a = measure of the first angle
b = measure of the second angle
c = measure of the third angle
then:
1) 36 + b + (3b-28) = 180 ⇒ )Define your variable. Write your equation and solve)
b + 3b + 36 - 28 = 180
4b + 8 = 180
4b = 180 - 8
4b = 172
b = 172/4
2) b = 43° ⇒ measure of the second angle
c = 3b - 28
c = 3*43 - 28
c = 129 - 28
3) c = 101° ⇒ measure of the third angle
Check:
36° + 43° + 101° = 180°
Answer:
50 lbs
Step-by-step explanation:
UPS: 8 + .20p
FedEx: 3 + .30p
8 + .20p = 3 + .30p
8 = 3 + .10p
5 = .10p
p = 50
