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Andre45 [30]
3 years ago
5

Solve the simultaneous equations

Mathematics
1 answer:
Contact [7]3 years ago
7 0

Answer:

The solution for given system of equations is: x = 6 and y = 3

Or

(6,3)

Step-by-step explanation:

Given equations are:

3x+4y=30\ \ \ Eqn\ 1\\3x-y=15\ \ \ \ Eqn\ 2

There are three methods to solve simultaneous equations

  1. Elimination
  2. Substitution
  3. Co-efficient method

We will use the elimination method as the coefficients of x in both equations are already same

Subtracting equation 2 from equation 1

3x+4y - (3x-y) = 30-15\\3x+4y-3x+y = 15\\5y = 15\\\frac{5y}{5} = \frac{15}{5}\\y = 3

Putting y = 3 in equation 2

3x-3 = 15\\3x = 15+3\\3x = 18\\\frac{3x}{3} = \frac{18}{3}\\x =  6

Hence,

The solution for given system of equations is: x = 6 and y = 3

Or

(6,3)

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Find all solutions to 8x³-10x² - 21x + 18 = 0 if x= 2 is one solution.
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<h3>How does one solve a three-degree equation?</h3>

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<h3>According to the given data:</h3>

8x³-10x² - 21x + 18 = 0

x= 2

substituting the value in the equation we get:

8x³-10x² - 21x + 18 = 0

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68 - 40 - 42 + 18 = 0

4 = 0

According to the given equation  8x³-10x² - 21x + 18 = 0 the other value of x will be 4.

To know more about cubic equation visit:

brainly.com/question/13730904

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