Question

Solve the simultaneous equations

Answer 1

Answer:

The solution for given system of equations is: x = 6 and y = 3

Or

(6,3)

Step-by-step explanation:

Given equations are:

$3x+4y=30\ \ \ Eqn\ 1\\3x-y=15\ \ \ \ Eqn\ 2$

There are three methods to solve simultaneous equations

1. Elimination
2. Substitution
3. Co-efficient method

We will use the elimination method as the coefficients of x in both equations are already same

Subtracting equation 2 from equation 1

$3x+4y - (3x-y) = 30-15\\3x+4y-3x+y = 15\\5y = 15\\\frac{5y}{5} = \frac{15}{5}\\y = 3$

Putting y = 3 in equation 2

$3x-3 = 15\\3x = 15+3\\3x = 18\\\frac{3x}{3} = \frac{18}{3}\\x = 6$

Hence,

The solution for given system of equations is: x = 6 and y = 3

Or

(6,3)