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NARA [144]
3 years ago
13

How do the areas of triangle ABC and DEF compare?

Mathematics
1 answer:
guapka [62]3 years ago
6 0

Answer:

C: The area of ABC is 1 square unit greater than the

area of ADEF

Step-by-step explanation:

Due to the area of triangle ABC and triangle DEF, the ABC triangle has dimensions that are 1 square unit greater that the area of ADEF. This is because the lines have different lengths. Good Luck on the Rest of Your Questions!!

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2/3 divided by 1/4 ill give brainliest
Virty [35]

2/3 ÷ 1/4

2/3 ×4/1 (by reciprocal)

2/3 × 4

8/3

4 0
2 years ago
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Describe these sets 2,4,8,16,32,64​
rosijanka [135]

Answer: They are all divisible by 2.

Step-by-step explanation: They all have 2 in common. If you divide them by 2, they all work. Also, if you simplify all to the lowest number, they equal 2 except 2 itself which equals 1.

3 0
2 years ago
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A sailboat leaves port and sails 12 kilometers west and then 9 kilometers north.
GarryVolchara [31]

Answer:  The sailboat is at a distance of 15 km from the port.

Step-by-step explanation:  Given that a sail boat leaves port and sails 12 kilometers west and then 9 kilometers north.

We are to find the distance between the sailboat from the port in kilometers.

Since the directions west and north are at right-angles, we can visualize the movement of the sailboat in the form of a right-angled triangle as shown in the attached figure.

The sailboat moves leaves the port at P and reach O after sailing 12 km west. From point O, again it moves towards north 9 km and reach the point S.

PS = ?

Using the Pythagoras theorem, we have from right-angled triangle SOP,

Thus, the sailboat is at a distance of 15 km from the port.

3 0
3 years ago
PLEASE HELP!!! Write the equation of a line that goes through the point (6, 3) and is perpendicular to the line y = 4x + 1.
Tpy6a [65]

For this case we have that by definition, the equation of a line in the point-slope form is given by:

y-y_ {0} = m (x-x_ {0})

Where:

m: It is the slope of the line and (x_ {0}, y_ {0})is a point through which the line passes.

We have the following equation of the slope-intersection form:

y = 4x + 1

Where the slope is m = 4

By definition, if two lines are perpendicular then the product of their slopes is -1.

Thus, a perpendicular line will have a slope:

m_ {2} = \frac {-1} {m_ {1}}\\m_ {2} = \frac {-1} {4}\\m_ {2} = - \frac {1} {4}

Thus, the equation will be of the form:

y-y_ {0} = - \frac {1} {4} (x-x_ {0})

Finally we substitute the given point and we have:

y-3 = - \frac {1} {4} (x-6)

Answer:

Option B

8 0
3 years ago
Can someone help me for 20 points please? Thanks, make sure it is correct!
zzz [600]
Yes what do you need help with
8 0
3 years ago
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