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NARA [144]
4 years ago
13

How do the areas of triangle ABC and DEF compare?

Mathematics
1 answer:
guapka [62]4 years ago
6 0

Answer:

C: The area of ABC is 1 square unit greater than the

area of ADEF

Step-by-step explanation:

Due to the area of triangle ABC and triangle DEF, the ABC triangle has dimensions that are 1 square unit greater that the area of ADEF. This is because the lines have different lengths. Good Luck on the Rest of Your Questions!!

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Plz help i will give brainliest
Aneli [31]

Answer:

m\angle XYZ = 70\degree

Step-by-step explanation:

By exterior angle theorem:

4x° = 2x° + 70°

4x° - 2x° = 70°

2 x° = 70°

2x = 70

x = 70/2

x = 35

m\angle XYZ = 2x\degree

m\angle XYZ = 2\times 35\degree

m\angle XYZ = 70\degree

4 0
3 years ago
Read 2 more answers
Ava borrowed some money from her friend in order to help buy a new video game system. Ava agreed to pay back her friend $2 per w
nydimaria [60]

We know that Ava is paying $2 dollars per week so if L is the money that she owes and t is the number of weeks, and I is the initial debt so we can write an equation like:

L=I-2t

Now we can replace the info we have to find the value of I so:

10=I-2(5)

and we solve for I

\begin{gathered} I=10+10 \\ I=20 \end{gathered}

So the final equation will be:

L=20-2t

8 0
1 year ago
Can someone please help me!
Anuta_ua [19.1K]

To solve the formula for v1, we must get this variable alone on one side of the equation. To do this, we use the reverse order of operations to move the other variables to the other side of the equation.

First, we begin by multiplying both sides of the equation by t, so that we can get rid of the denominator on the right side.

a = (v1 - v0)/t

a(t) = v1 - v0

Next, we must add v0 to both sides of the equation. This will get the variable v1 completely alone on the right side of the equation, giving us our answer.

(at) + v0 = v1

We should rearrange the equation so that v1 is the left side of the equation.

v1 = at + v0 (your answer)

Hope this helps!

3 0
3 years ago
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Sometimes one form is more beneficial than the other. Identify which form would be more helpful if you needed to do each task li
tankabanditka [31]
The surest way to get many of the points needed to plot a quadratic is to use the quadratic formula. This will give the roots (real or imaginary). It will give you the completed square form also called the vertex form (if you know how to use the discriminant). It can easily give you the y intercept (which you can find before you use the quadratic formula).  It gives the max or min upon solution.

The easiest one to use if it is available to you, is factoring. The quadratic may not be factorable. But if it is and you can see it, then this gives you 2 points immediately (the roots) and a third without much trouble (the y intercept). Factoring will also give you the x value of the vertex. (Find the average between the 2 roots)

This needs an example
Suppose you have y = (x - 5)(x - 9) The roots are 5 and 9, correct? So the x value of the vertex is (5 + 9)/2 = 7 It always works.

Completing the square always gives you the minimum or maximum right away. For example if you have y = (x - 2)^2 - 5 it means you have the vertex at (2,-5) You can get the roots easily enough.  So this form is useful, but not as sure as the quadratic equation or as simple as factoring.

Graphing is the most certain way to check your answer. I find it the most useful thing to do with modern computers. There are all sorts of things that a graph will reveal that algebra by itself might be laborious and prone to leading you to mistakes. Graphing tends to correct that problem.
6 0
3 years ago
PLZ, HURRY WILL GIVE BRAINILEST TO CORRECT ANSWER!
Sergeeva-Olga [200]

Answer:

c 4/5

Step-by-step explanation:

marry chrismas

6 0
3 years ago
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