The points you found are the vertices of the feasible region. I agree with the first three points you got. However, the last point should be (25/11, 35/11). This point is at the of the intersection of the two lines 8x-y = 15 and 3x+y = 10
So the four vertex points are:
(1,9)
(1,7)
(3,9)
(25/11, 35/11)
Plug each of those points, one at a time, into the objective function z = 7x+2y. The goal is to find the largest value of z
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Plug in (x,y) = (1,9)
z = 7x+2y
z = 7(1)+2(9)
z = 7+18
z = 25
We'll use this value later.
So let's call it A. Let A = 25
Plug in (x,y) = (1,7)
z = 7x+2y
z = 7(1)+2(7)
z = 7+14
z = 21
Call this value B = 21 so we can refer to it later
Plug in (x,y) = (3,9)
z = 7x+2y
z = 7(3)+2(9)
z = 21+18
z = 39
Let C = 39 so we can use it later
Finally, plug in (x,y) = (25/11, 35/11)
z = 7x+2y
z = 7(25/11)+2(35/11)
z = 175/11 + 70/11
z = 245/11
z = 22.2727 which is approximate
Let D = 22.2727
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In summary, we found
A = 25
B = 21
C = 39
D = 22.2727
The value C = 39 is the largest of the four results. This value corresponded to (x,y) = (3,9)
Therefore the max value of z is z = 39 and it happens when (x,y) = (3,9)
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Final Answer: 39
The value of Tan 3.4 is 0.059410947 rounded off to four decimal places would equal to 0.0594, letter B. This is your answer if your calculator is in the degree mode.
Tangent or Tan is one of the trigonometry functions. It represents TOA in the sohcahtoa mnemonic which means Tan = Opposite / Adjacent
Answers:
(sin40)/(cos40) and
(cos50)/(sin50)
The first part says the sum of the squares of two consecutive integers or in other words (x)(x)+(x+1)(x+1) so we can cross out A because 2 and 3 are prime numbers (no factors) we can cross out all the others because the square root of 52 is not an integer so any equation with 52 in it does not satisfy the requirement. so none of them are corect. additionally, some of the equations are obviously false such as 52+62=61
