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2 years ago

If f(x) = (3+x)/ (x-3),what is f(a+ 2)?

1 answer:

4 0

To answer items such as this, we directly substitute the a + 2 to the all the x's in the function such that,
f(a + 2) = (3 + a + 2) / (a + 2 - 3)
Simplifying the function generated above,
f(a + 2) = (5 + a) / (a - 1)

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3. [25 points]. Answer each of the following questions in the context of algorithms.

Nimfa-mama [501]

Answer:

also its 25

Step-by-step explanation:

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2 years ago

A random sample of 15 dvd players has a mean price of $64.30 and a standard deviation of $5.60. find a 95% confidence interval f

makkiz [27]

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2 years ago

Solve the following equation. Remember to check for extraneous solutions 1/(x-6) + (x/(x-2)) = (4/(x²-8x+12)).

xxMikexx [17]

Answer:

-1, 2, 6

Step-by-step explanation:

We have to solve the equation as follows: 1/(x-6) + (x/(x-2)) = (4/(x²-8x+12)).

Now, we have, $\frac{1}{x-6} +\frac{x}{x-2} = \frac{4}{x^{2}-8x+12 }$

⇒ $\frac{(x-2)+x(x-6)}{(x-2)(x-6)} = \frac{4}{x^{2}-8x+12 }$

⇒ $\frac{x-2+x^{2}-6x }{(x-2)(x-6)} =\frac{4}{(x-2)(x-6)}$

⇒ $\frac{(x-2)(x-6)}{x^{2}-5x-2 }=\frac{(x-2)(x-6)}{4}$

⇒ $(x-2)(x-6)[\frac{1}{x^{2} -5x-2} -\frac{1}{4} ]=0$

⇒ $(x-2)(x-6) =0$ or, $[\frac{1}{x^{2} -5x-2} -\frac{1}{4} ]=0$

If, (x-2)(x-6) =0, then x=2 or x=6

If, $[\frac{1}{x^{2} -5x-2} -\frac{1}{4} ]=0$ , then $x^{2} -5x-2=4$

and (x-6)(x+1) =0

Therefore, x=6 or -1

So the solutions for x are -1, 2 6. (Answer)

4 0

3 years ago

Plz help asap with explanation and will get the brilliant

Elina [12.6K]

3x + y = -3
-2x + y = 7
Use elimination method
Subtract both equations
5x = -10, x = -2
Plug in -2 for x (any equation)
3(-2) + y = -3
-6 + y = -3
y = 3

Solution: x = -2, y = 3
Or as a coordinate: (-2, 3)

8 0

2 years ago

Read 2 more answers

I JUST NEED HELP PLEASE!! AHH!!~∆~

mafiozo [28]

Answer:

Step-by-step explanation:

take theta as reference angle

using sin rule

sin theta=opposite/hypotenuse

sin theta=5/13

sin theta=0.38

theta=sin 23

therefore the value of theta is 23 degree

8 0

2 years ago