Answer:
2×(1+10)
Step-by-Step
You are just substituting in where the parenthesis go.
But I am not entirely sure.
Because x²+1 has an imaginary solution so you can’t find a value to put on the side for synthetic division
Answer:
f(g(2))=84
Step-by-step explanation:
Step one:
Given data
f(x)= x*2 +3
g(x) = 4x + 1
Step two
Let us find g(2) first then we proceed to find f(g(2))
g(2)=4(2) +1
g(2)=8+1
g(2)=9
Since g(2)=9
f(g(2))=x*2 +3
f(g(2))=9*2 +3
f(g(2))=81+3
f(g(2))=84
Problem
For a quadratic equation function that models the height above ground of a projectile, how do you determine the maximum height, y, and time, x , when the projectile reaches the ground
Solution
We know that the x coordinate of a quadratic function is given by:
Vx= -b/2a
And the y coordinate correspond to the maximum value of y.
Then the best options are C and D but the best option is:
D) The maximum height is a y coordinate of the vertex of the quadratic function, which occurs when x = -b/2a
The projectile reaches the ground when the height is zero. The time when this occurs is the x-intercept of the zero of the function that is farthest to the right.
Answer:
55
Step-by-step explanation:
hope it helps you.....