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Maurinko [17]
3 years ago
13

there are 11 kids at a birthday party if there are six girls and five boys at the party which fraction of the kids are boys

Mathematics
1 answer:
timofeeve [1]3 years ago
4 0
11 kids total and there’s 6 girls and 5 boys so that means there’s 5/11 boys and for girls it’s 6/11
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kumpel [21]
Are you asking for a definition
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3 years ago
What missing angle of the figure
aniked [119]

Answer:

138

Step-by-step explanation:

152+125=277

277-135=142

around 138

4 0
3 years ago
Simplify the following​
den301095 [7]

Answer:

1) 11\sqrt{3}

2) 2\sqrt{2}

3) 20\sqrt{3}  + 15\sqrt{2}

4) 53 + 12\sqrt{10}

5) -2

6) 7\sqrt{2}  - 5\sqrt{3}

Step-by-step explanation:

1) 2\sqrt{12} + 3\sqrt{48} - \sqrt{75}

=(2 × 2\sqrt{3} )+ (3 × 4\sqrt{3}) - 5\sqrt{3}

= 4\sqrt{3} + 12\sqrt{3} - 5\sqrt{3}

= 11\sqrt{3}

2) 4\sqrt{8} -2\sqrt{98} + \sqrt{128}

= (4 × 2\sqrt{2}) - (2 × 7\sqrt{2}) + 8\sqrt{2}

= 8\sqrt{2} - 14\sqrt{2} +8\sqrt{2}

= 2\sqrt{2}

3) 5\sqrt{12\\} - 3\sqrt{18} + 4 \sqrt{72}  +2\sqrt{75}

= 5× 2\sqrt{3} - 3×3\sqrt{2} + 4×6\sqrt{2} + 2×5\sqrt{3}

= 10\sqrt{3} - 9\sqrt{2} +24\sqrt{2} +10\sqrt{3}

= 20\sqrt{3}  + 15\sqrt{2}

4) (2\sqrt{2}  + 3\sqrt{5} )^{2}

= 8 + 12\sqrt{10} + 45

= 53 + 12\sqrt{10}

5) (1+\sqrt{3} ) (1-\sqrt{3} )

= 1 - 3

= -2

6) (2\sqrt{6} -1) (\sqrt{3} -\sqrt{2}  )

= 2\sqrt{18}-2\sqrt{12}  -\sqrt{3}  +\sqrt{2}

= 2×3\sqrt{2} - 2×2\sqrt{3} - \sqrt{3} + \sqrt{2}

= 6\sqrt{2}  - 4\sqrt{3} -\sqrt{3} +\sqrt{2}

= 7\sqrt{2}  - 5\sqrt{3}

Hope the working out is clear and will help you. :)

5 0
3 years ago
Read 2 more answers
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r-ruslan [8.4K]

Answer:

-20

Step-by-step explanation:

(r + b − g)(b + g)

we have fom statement:

r = 9    

b = 5

g= −6

so we have:

(r + b − g)(b + g)= (9+5-(-6))*(5+(-6))

(r + b − g)(b + g)= (14+6)*(-1)

(r + b − g)(b + g)= -20

8 0
3 years ago
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Nikitich [7]
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x=3/8
Lets say n is the value of how many people ate with 7 people
7x=n
now substitute
7x=n
7(3/8)=n
21/8=n
n=2 5/8
7 0
3 years ago
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